I can't seem to make my regex work so i think I must be doing something wrong. If anyone could help me out that would be great.

here is my regex function

let validatePlate = (plate) => {
  var re = /(^[A-Z]{2}[0-9]{2}\s?[A-Z]{3}$)|(^[A-Z][0-9]{1,3}[A-Z]{3}$)|(^[A-Z]{3}[0-9]{1,3}[A-Z]$)|(^[0-9]{1,4}[A-Z]{1,2}$)|(^[0-9]{1,3}[A-Z]{1,3}$)|(^[A-Z]{1,2}[0-9]{1,4}$)|(^[A-Z]{1,3}[0-9]{1,3}$)|(^[A-Z]{1,3}[0-9]{1,4}$)|(^[0-9]{3}[DX]{1}[0-9]{3}$)/

    return re.test(plate);
};

and I use it in textInput as follows:

<TextInput
onChange={validatePlate}
editable={true}
}}>
Hello
</TextInput>

It still allows special characters, etc.

FYI: The regex is for filtering UK numberplates.

I can't seem to make my regex work so i think I must be doing something wrong. If anyone could help me out that would be great.

here is my regex function

let validatePlate = (plate) => {
  var re = /(^[A-Z]{2}[0-9]{2}\s?[A-Z]{3}$)|(^[A-Z][0-9]{1,3}[A-Z]{3}$)|(^[A-Z]{3}[0-9]{1,3}[A-Z]$)|(^[0-9]{1,4}[A-Z]{1,2}$)|(^[0-9]{1,3}[A-Z]{1,3}$)|(^[A-Z]{1,2}[0-9]{1,4}$)|(^[A-Z]{1,3}[0-9]{1,3}$)|(^[A-Z]{1,3}[0-9]{1,4}$)|(^[0-9]{3}[DX]{1}[0-9]{3}$)/

    return re.test(plate);
};

and I use it in textInput as follows:

<TextInput
onChange={validatePlate}
editable={true}
}}>
Hello
</TextInput>

It still allows special characters, etc.

FYI: The regex is for filtering UK numberplates.

• javascript
• reactjs
• typescript
• react-native

Share Improve this question Follow asked Feb 12, 2020 at 16:25 UnluckyLADUnluckyLAD 18933 silver badges2121 bronze badges 1

• 1 You are not returning any string, you are returning the validation result, true or false – Ian Vasco Commented Feb 12, 2020 at 16:30

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1 Answer 1

Sorted by: Reset to default 3

Have you tried wrapping your regexp in new RegExp()

For example:

const nameRegex = new RegExp(/^[a-z ,.'-]+(\s)([a-z ,.'-])+$/i);
if (nameRegex.test(inputValue)) {
    doSomething();
}