I have this simple test file:

describe('index', () => {
    it('should bootstrap the app', async () => {
        const root = <div />;
        jest.spyOn(ReactDOM, 'render');
        ...
        ReactDOM.render.mockImplementationOnce(() => {} );
        ...
        ReactDOM.render.mockRestore();
    } );
} );

I get the following typescript error: "TS2339: property 'mockImplementationOnce' does not exist on type 'Renderer'"

Anyone knows how I can make TypeScript recognize jest mock methods?

I have this simple test file:

describe('index', () => {
    it('should bootstrap the app', async () => {
        const root = <div />;
        jest.spyOn(ReactDOM, 'render');
        ...
        ReactDOM.render.mockImplementationOnce(() => {} );
        ...
        ReactDOM.render.mockRestore();
    } );
} );

I get the following typescript error: "TS2339: property 'mockImplementationOnce' does not exist on type 'Renderer'"

Anyone knows how I can make TypeScript recognize jest mock methods?

• javascript
• reactjs
• typescript
• jestjs

Share Improve this question Follow edited Jun 19, 2018 at 16:50 Kizer asked Jun 18, 2018 at 7:24 KizerKizer 1,66622 gold badges1717 silver badges2424 bronze badges

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2 Answers 2

Sorted by: Reset to default 4

You can use type assertion to hint typescript that render is a SpyInstance

const render = ReactDOM.render as any as SpyInstance;
render.mockImplementationOnce(() => { });
...

Instead of using ReactDOM.render which doesn't have the proper type, use the returned value of jest.spyOn(ReactDOM, 'render') which is a Jest mock function (cf. spyOn() doc) i.e. with the expected type for TypeScript, including both methods mockImplementationOnce() and mockRestore().

const reactRenderMock = jest.spyOn(ReactDOM, 'render');
// ...
reactRenderMock.mockImplementationOnce(() => {} );
// ...
reactRenderMock.render.mockRestore();