javascript - Uncaught TypeError: Cannot read property 'firstChild' of null error message - Stack Overflow

I've been trying to pass through JS variables via the onChange event but keep receiving the Uncaug

I've been trying to pass through JS variables via the onChange event but keep receiving the

Uncaught TypeError: Cannot read property 'firstChild' of null

under Google Chrome. Here is my code below:

    artistID = album_select.substring(0, album_select.indexOf('/'));
    albumID = album_select.substring(album_select.indexOf('/')+1, album_select.length);     
    var count = 0;
    var tracklist = '';
    for(track in albumlist[albumID][2]){
        count++;
        tracklist+="<option id='"+album+"'>"+track+"</option>";             
        } 
    hstr+="<form><select size='"+count+"' onChange='parent.loadSong(this.value, document.getElementById(\"album_select\").firstChild.nodeValue, document.getElementById(\"artistID\").firstChild.nodeValue)' style='font-size:2em;'>";
    hstr+=tracklist;
    hstr+="</form></select>";

I've been trying to pass through JS variables via the onChange event but keep receiving the

Uncaught TypeError: Cannot read property 'firstChild' of null

under Google Chrome. Here is my code below:

    artistID = album_select.substring(0, album_select.indexOf('/'));
    albumID = album_select.substring(album_select.indexOf('/')+1, album_select.length);     
    var count = 0;
    var tracklist = '';
    for(track in albumlist[albumID][2]){
        count++;
        tracklist+="<option id='"+album+"'>"+track+"</option>";             
        } 
    hstr+="<form><select size='"+count+"' onChange='parent.loadSong(this.value, document.getElementById(\"album_select\").firstChild.nodeValue, document.getElementById(\"artistID\").firstChild.nodeValue)' style='font-size:2em;'>";
    hstr+=tracklist;
    hstr+="</form></select>";
Share Improve this question asked Dec 3, 2011 at 23:13 methuselahmethuselah 13.2k53 gold badges177 silver badges333 bronze badges 1
  • can u show the html for album_select and artistID please? – samach Commented Dec 3, 2011 at 23:30
Add a ment  | 

1 Answer 1

Reset to default 1

This part of the string:

document.getElementById(\"artistID\")

Is looking for an ID of "artistID".

I assume you meant to concatenate the variable.

"...document.getElementById('" + artistID + "')..."

Sounds like this one needs it too:

"...document.getElementById('" + album_select + "')..."

发布者:admin,转转请注明出处:http://www.yc00.com/questions/1745569421a4633591.html

相关推荐

发表回复

评论列表(0条)

  • 暂无评论

联系我们

400-800-8888

在线咨询: QQ交谈

邮件:admin@example.com

工作时间:周一至周五,9:30-18:30,节假日休息

关注微信