javascript - How to send Json data into database using Jquery and Ajax? - Stack Overflow

I have made form of customer details form when I click the button, It send Json data to customer. But m

I have made form of customer details form when I click the button, It send Json data to customer. But my code is not inserting data into database. I am new in web technology, please tell me where I am wrong.

my Script:

 <script>   
    $(document).ready(function(){              
            $("#btnBooking").on("click", function(){                   

                var uName = document.getElementById('userName').value;        
                var mailId = document.getElementById('addressemailId').value;           
                var mobNum = document.getElementById('userContactNumber').value;                    
                $.ajax({
                    url:"http://192.168.1.11/customerhomes/customer.php", 
                    type:"GET", 
                    dataType:"json", 
                    data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum}, 
                    //type: should be same in server code, otherwise code will not run
                    ContentType:"application/json", 
                    success: function(response){ 
                            alert("13");                                                 
                        }, 
                        error: function(err){ 
                        alert(JSON.stringify(err)); 
                    } 
                })              
            }); 
    });
</script>

form in html

<body>
    <div class="page-header text-center">
        <form >
            <div class="col-lg-8">                                  
                <div class="form-group">
                        <label class="col-lg-3 control-label">Name:<font style="color: red;">*</font></label>
                        <div class="col-lg-9">
                            <input type="text" class="form-control" id="userName" name="userName" placeholder="Full Name" value="">
                        </div>
                </div>


                <div class="form-group">
                    <label class="col-lg-3 control-label">Mobile:<font style="color: red;">*</font></label>
                    <div class="col-lg-9">
                        <input type="text" class="form-control" id="userContactNumber" name="userContactNumber" type="number" placeholder="" onkeypress="enableKeys(event);" maxlength="10" placeholder="9966778888">
                    </div>
                </div>

                <div class="form-group">
                        <label class="col-lg-3 control-label">Email:<font style="color: red;">*</font></label>
                        <div class="col-lg-9">                                  
                            <input type="text" class="form-control" name="addressemailId" id="addressemailId" placeholder="[email protected]" value="">
                        </div>
                </div>  
                <div class="form-group marg-bot-45">
                    <label class="col-lg-3 control-label"></label>
                    <div class="col-lg-9">

                        <a href="" class="btn btn-info"  id="btnBooking">Confirm Booking</a>
                    </div>
                </div>
            </div>
        </form>
    </div>
</body>

server code

<?php
header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
mysql_connect("localhost","root","1234");
mysql_select_db("customer_details");
if(isset($_GET['type']))
{
    if($_GET['type']=="booking"){
        $name = $_GET ['Name'];
        $mail = $_GET ['Email'];
        $mobile = $_GET ['Mob_Num'];
        $query1 = "insert into customer(cust_name, cust_mobile, cust_email) values('$name','$mail','$mobile')";
        $result1=mysql_query($query1);
    }
}
else{
    echo "Invalid format";
}

I have made form of customer details form when I click the button, It send Json data to customer. But my code is not inserting data into database. I am new in web technology, please tell me where I am wrong.

my Script:

 <script>   
    $(document).ready(function(){              
            $("#btnBooking").on("click", function(){                   

                var uName = document.getElementById('userName').value;        
                var mailId = document.getElementById('addressemailId').value;           
                var mobNum = document.getElementById('userContactNumber').value;                    
                $.ajax({
                    url:"http://192.168.1.11/customerhomes/customer.php", 
                    type:"GET", 
                    dataType:"json", 
                    data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum}, 
                    //type: should be same in server code, otherwise code will not run
                    ContentType:"application/json", 
                    success: function(response){ 
                            alert("13");                                                 
                        }, 
                        error: function(err){ 
                        alert(JSON.stringify(err)); 
                    } 
                })              
            }); 
    });
</script>

form in html

<body>
    <div class="page-header text-center">
        <form >
            <div class="col-lg-8">                                  
                <div class="form-group">
                        <label class="col-lg-3 control-label">Name:<font style="color: red;">*</font></label>
                        <div class="col-lg-9">
                            <input type="text" class="form-control" id="userName" name="userName" placeholder="Full Name" value="">
                        </div>
                </div>


                <div class="form-group">
                    <label class="col-lg-3 control-label">Mobile:<font style="color: red;">*</font></label>
                    <div class="col-lg-9">
                        <input type="text" class="form-control" id="userContactNumber" name="userContactNumber" type="number" placeholder="" onkeypress="enableKeys(event);" maxlength="10" placeholder="9966778888">
                    </div>
                </div>

                <div class="form-group">
                        <label class="col-lg-3 control-label">Email:<font style="color: red;">*</font></label>
                        <div class="col-lg-9">                                  
                            <input type="text" class="form-control" name="addressemailId" id="addressemailId" placeholder="[email protected]" value="">
                        </div>
                </div>  
                <div class="form-group marg-bot-45">
                    <label class="col-lg-3 control-label"></label>
                    <div class="col-lg-9">

                        <a href="" class="btn btn-info"  id="btnBooking">Confirm Booking</a>
                    </div>
                </div>
            </div>
        </form>
    </div>
</body>

server code

<?php
header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
mysql_connect("localhost","root","1234");
mysql_select_db("customer_details");
if(isset($_GET['type']))
{
    if($_GET['type']=="booking"){
        $name = $_GET ['Name'];
        $mail = $_GET ['Email'];
        $mobile = $_GET ['Mob_Num'];
        $query1 = "insert into customer(cust_name, cust_mobile, cust_email) values('$name','$mail','$mobile')";
        $result1=mysql_query($query1);
    }
}
else{
    echo "Invalid format";
}
Share Improve this question edited Jan 17, 2015 at 9:56 Neelabh Singh asked Jan 17, 2015 at 8:59 Neelabh SinghNeelabh Singh 2,67812 gold badges55 silver badges91 bronze badges 5
  • It seems that you are sending json formatted data to php but on the server side you don't decode it --> check out this answer stackoverflow./questions/4343596/parsing-json-file-with-php – Velimir Tchatchevsky Commented Jan 17, 2015 at 9:06
  • Also, for learning purposes, have a look at prepared statements here (at as I believe one of the most useful answers around) – Jan Legner Commented Jan 17, 2015 at 9:13
  • @ Jan Legner, thanks for reply but this link about for sqlinjection.... – Neelabh Singh Commented Jan 17, 2015 at 9:16
  • any errors while executing code ? – Anand Patel Commented Jan 17, 2015 at 9:18
  • You need to decode your json data, when you send them to php. – ilgaar Commented Jan 17, 2015 at 9:38
Add a ment  | 

3 Answers 3

Reset to default 1

Use this

JavaScript Code:

<script>
        $(document).ready(function(){
            $("#btnBooking").on("click", function(e){

                // as you have used hyperlink(a tag), this prevent to redirect to another/same page
                e.preventDefault();

                // get values from textboxs  
                var uName = $('#userName').val();
                var mailId = $('#addressemailId').val();
                var mobNum = $('#userContactNumber').val();

                $.ajax({
                    url:"http://192.168.1.11/customerhomes/customer.php",
                    type:"GET",
                    dataType:"json",
                    data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum},
                    //type: should be same in server code, otherwise code will not run
                    ContentType:"application/json",
                    success: function(response){
                        alert(JSON.stringify(response));
                    },
                    error: function(err){
                        alert(JSON.stringify(err));
                    }
                })
            });
        });
    </script>

PHP Code

<?php
header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
 mysql_connect("localhost","root","1234");
 mysql_select_db("customer_details");
if(isset($_GET['type']))
{
    $res = [];

    if($_GET['type'] =="booking"){
        $name  = $_GET ['Name'];
        $mail  = $_GET ['Email'];
        $mobile  = $_GET ['Mob_Num'];
        $query1  = "insert into customer(cust_name, cust_mobile, cust_email) values('$name','$mail','$mobile')";
        $result1 = mysql_query($query1);

        if($result1)
        {
            $res["flag"] = true;
            $res["message"] = "Data Inserted Successfully";
        }
        else
        {
            $res["flag"] = false;
            $res["message"] = "Oppes Errors";
        }

    }
}
else{
    $res["flag"] = false;
    $res["message"] = "Invalid format";
}

    echo json_encode($res);
?>

If data is inserted successfully it return true flag with message, otherwise false flag with message

I would first of all change the "GET" to a "POST" on both the ajax call and the receiving PHP page on the server.

Secondly, I'd check that the values are actually being passed to the PHP page by using echo to output each of them on the PHP side. That way you'll know at least the values are ing through.

JavaScript:

var uName = $('#userName').val();        
var mailId = $('#addressemailId').val();           
var mobNum = $('userContactNumber').val();                    
$.ajax({
    url:"http://192.168.1.11/service4homes/customer.php", 
    type:"POST", 
    data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum}, 
    plete: function(response){ 
        var test = $.parseHTML(response);
        alert(test);
    }
 });

PHP Code:

echo $_POST["type"];
echo $_POST["Name"];
//etc...

try this it might help you.

in your ajax function:

1st change : ContentType:"application/json" to contentType: "application/json; charset=utf-8"

2nd

in data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum} change to data:{type1:"booking",Name:uName, Email:mailId, Mob_Num:mobNum}. see you set type as GET in ajax function so i am thinking that "type" is reserved word, so it might not work. and also check your url where you are sending ajax request if it is correct or not bcoz you are using ip address.

in your server code i am seeing typo. there is space between

$_GET ['name'], $_GET ['Email'], $_GET ['Mob_Num'].

there should be no space so change it to this,

$_GET['name']

$_GET['Email']

$_GET['Mob_Num']

发布者:admin,转转请注明出处:http://www.yc00.com/questions/1745485604a4629753.html

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