I'm trying to remove the printed single quotations which occur while running the following code.

I've tried playing around with the replace(/['"]+/g, ''but I'm not getting this correctly.

var arr = ["Alpha", "Omega", "Delta"];
var symbol = "weee";
for(x=0; x<arr.length; x++){
    console.log(x,symbol,arr[x]);
}

This returns:

0 'weee' 'Alpha'

1 'weee' 'Omega'

2 'weee' 'Delta' 

I'm trying to remove the printed single quotations which occur while running the following code.

I've tried playing around with the replace(/['"]+/g, ''but I'm not getting this correctly.

var arr = ["Alpha", "Omega", "Delta"];
var symbol = "weee";
for(x=0; x<arr.length; x++){
    console.log(x,symbol,arr[x]);
}

This returns:

0 'weee' 'Alpha'

1 'weee' 'Omega'

2 'weee' 'Delta' 

• javascript
• arrays
• console.log

Share Improve this question Follow edited Mar 15, 2017 at 2:38 aircraft 27k2929 gold badges101101 silver badges174174 bronze badges asked Mar 15, 2017 at 2:33 dpxdpx 11722 silver badges1010 bronze badges 1

• don't use chrome, it's the only console that does that (well, not quite ... my console uses double quotes in the output) ... anyway ... who cares how strings a shown in a debugging tool - it makes no difference to the code – Jaromanda X Commented Mar 15, 2017 at 2:49

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1 Answer 1

Sorted by: Reset to default 7

If the types of console.log parameters are different, string type will be marked by quotation marks, so you can make the parameters to a single string, just like:

 console.log(x + ' ' + symbol + ' ' +arr[x]);