the code is:

console.log("\1" === "\u0001");//true
console.log("\01" === "\x01");//true
console.log("\001" === "\u0001");//true

why "\001" === "\u0001" is true,who can tell me why?

the code is:

console.log("\1" === "\u0001");//true
console.log("\01" === "\x01");//true
console.log("\001" === "\u0001");//true

why "\001" === "\u0001" is true,who can tell me why?

• javascript
• escaping

Share Improve this question Follow edited Jul 26, 2014 at 4:15 hippietrail 17.1k2121 gold badges109109 silver badges179179 bronze badges asked Oct 10, 2012 at 15:30 artwlartwl 3,58277 gold badges4141 silver badges5555 bronze badges 2

• 2 Because they're all the same character? If you were expecting the form seen in the literal syntax to be pared, you'd need to escape the \ character. console.log("\\1" === "\\u0001");// false – I Hate Lazy Commented Oct 10, 2012 at 15:34
• They are all the same character. Those are different ways to escape it. – gen_Eric Commented Oct 10, 2012 at 15:35

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1 Answer 1

Sorted by: Reset to default 5

All of those strings are a single character; namely, Unicode code point 1.

Those are different ways of escaping it in the string literal.