I'm creating 2 objects based on given values in my jest test and expect that they would be equal except of the property uuid which is generated indevidualy for each object.

uuid can be deeply nested multiple times. for example:

const object1 = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' /* and so on */ }] }];
const object2 = { uuid: '7657657', name: 'xxx', branches: [{ uuid: '443444', children: [{ uuid: '09809' }] }];

How can I pare the objects, ignoring uuid property?

I'm creating 2 objects based on given values in my jest test and expect that they would be equal except of the property uuid which is generated indevidualy for each object.

uuid can be deeply nested multiple times. for example:

const object1 = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' /* and so on */ }] }];
const object2 = { uuid: '7657657', name: 'xxx', branches: [{ uuid: '443444', children: [{ uuid: '09809' }] }];

How can I pare the objects, ignoring uuid property?

• javascript
• jestjs
• equality

Share Improve this question Follow edited Aug 23, 2021 at 10:20 fullstack asked Aug 23, 2021 at 10:05 fullstackfullstack 84477 silver badges2222 bronze badges 1

• You can omit keys with _.omit and deep pare objects with _.isEqual – jabaa Commented Aug 23, 2021 at 10:11

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3 Answers 3

Sorted by: Reset to default 3

You can remove uuid first than pare them.

const object1 = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' /* and so on */ }] }]};
const object2 = { uuid: '7657657', name: 'xxx', branches: [{ uuid: '443444', children: [{ uuid: '09809' }] }]};

const removeUuid = o => {
  if (o) {
    switch (typeof o) {
    case "object":
      delete o.uuid;
      Object.keys(o).forEach(k => removeUuid(o[k]));
      break;
    case "array":
      o.forEach(a => removeUuid(a));
    }
  }
}

removeUuid(object1);
removeUuid(object2);

expect(object1).toBe(object2);

                                

You can use expect.any to ignore uuid attribute. Just make sure that the attributes are existing, and the uuid is a string:

describe("Compare 2 objects", () => {
  it("should ...", () => {
    const actual = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' }] }] };

    const expected = {
      uuid: expect.any(String), // <--
      name: 'xxx',
      branches: [{ uuid: expect.any(String), children: [{ uuid: expect.any(String) }] }]
    };

    expect(actual).toEqual(expected);
  });
});

I succeeded to achieve this with the following solution:

const object1 = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' /* and so on */ }] }] };
const object2 = { uuid: '7657657', name: 'xxx', branches: [{ uuid: '443444', children: [{ uuid: '09809' }] }] };

const pareExcludeKeys = (object1, object2, excludeKeys = []) => {
  if (Object.keys(object1).length !== Object.keys(object2).length) return false;
  return Object.entries(object1).reduce((isEqual, [key, value]) => {
    const isValueEqual = typeof value === 'object' && value !== null
      ? pareExcludeKeys(value, object2[key], excludeKeys) 
      : excludeKeys.includes(key) || object2[key] === value;
    return isEqual && isValueEqual;
  }, true);
};

console.log(pareExcludeKeys(object1, object2, ['uuid']));