For the string, "http://localhost:9090/calculator?oper=add&n1=10&n2=20",

console.log(url.parse(req.url).query);
// gives `oper=add&n1=10&n2=20`

whereas

console.log(querystring.parse(req.url));
// gives { '/calculator?oper': 'add', n1: '10', n2: '20' }`

However, I'm not able to split it as these are objects, and not Strings. How do I convert them to strings?

For the string, "http://localhost:9090/calculator?oper=add&n1=10&n2=20",

console.log(url.parse(req.url).query);
// gives `oper=add&n1=10&n2=20`

whereas

console.log(querystring.parse(req.url));
// gives { '/calculator?oper': 'add', n1: '10', n2: '20' }`

However, I'm not able to split it as these are objects, and not Strings. How do I convert them to strings?

• javascript
• string
• node.js
• url
• query-string

Share Improve this question Follow edited Aug 23, 2014 at 1:45 Colin Brock 21.6k99 gold badges4949 silver badges6262 bronze badges asked Aug 23, 2014 at 1:41 IAMTubbyIAMTubby 1,68744 gold badges2828 silver badges4242 bronze badges 3

• 5 I think request.url is already a string, why do you want to convert it to a string? The output of querystring.parse(req.url) is already splited, why do you want to split it? What output are you expecting? – Volune Commented Aug 23, 2014 at 1:53
• 1 @Volune : Thanks, yes request.url is a string indeed, I was confused, sorry. >The output of querystring.parse(req.url) is already splited But how do I access the zero'th object of this array ?{ '/calculator?oper': 'add', n1: '20', n2: '10' } I can access the n1 and n2 elements as follows. codevar temp = querystring.parse(req.url); console.log(temp.n1); console.log(temp.n2); But as I said, I'm unable to access the zero'th object. PS : I'm having a tough time trying to wrap in code and make bold etc. Can someone point me to a link where I can learn these for Stack Overflow – IAMTubby Commented Aug 23, 2014 at 8:19
• 1 Please try to clarify your question with what you just said, and fix your question's title. – Volune Commented Aug 23, 2014 at 9:47

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 1

As you can see in what you provided, querystring.parse(req.url) mixed the url path with the key of the zero'th value. This means that querystring.parse should not be called on a full url, but only on the query part of the url. You can do that by using querystring.parse on the result of url.parse:

var parsedUrl = url.parse(testUrl); //would be url.parse(req.url)
var parsedQuery = querystring.parse(parsedUrl.query);

Now you can do parsedQuery.oper, parsedQuery.n1, parsedQuery.n2

Example

---

If for some reason you want to iterate the parsedQuery (for example if you don't know the keys are oper, n1, n2, ...), you can do it this way:

var parsedQueryKeys = Object.keys(parsedQuery);
parsedQueryKeys.forEach(function(key) {
    console.log( key, parsedQuery[key] );
});

(There are multiple other solutions to iterate an object)

---

Finally, some libraries automate the parsing for you, so you can directly ask for the query values.

For example, with express's req.param:

console.log( req.param('oper'), req.param('n1'), req.param('n2') );

Find express on npm

Just use object.toString() to convert any variable into a string. Most scalar types and arrays will be converted. Other objects might need to have the method implemented, otherwise they will just return the text [Object] or something.

The second case it looks like console.log() used JSON.stringify(object), probably because the object doesn't have a method toString() implemented.