Folks, Trying to include other .js files to be able to export from a module in the following manner. This will make the main module more readable. I am trying to include code from other functions.

I suppose its not the correct way. Can someone guide me in the right direction?

main module file:

module.exports = {
    eval(fs.readFileSync('./extras/foo.js')+'');

    fdsa: function (barf, callback) {
    },
    asdf: function (barf, callback) {
    },
}

foo.js:

foo: function (barf, callback) {
     ...
     callback(err, result);
}

Folks, Trying to include other .js files to be able to export from a module in the following manner. This will make the main module more readable. I am trying to include code from other functions.

I suppose its not the correct way. Can someone guide me in the right direction?

main module file:

module.exports = {
    eval(fs.readFileSync('./extras/foo.js')+'');

    fdsa: function (barf, callback) {
    },
    asdf: function (barf, callback) {
    },
}

foo.js:

foo: function (barf, callback) {
     ...
     callback(err, result);
}

• javascript
• node.js

Share Improve this question Follow asked Mar 2, 2014 at 0:00 CmagCmag 15.8k2626 gold badges9797 silver badges147147 bronze badges 3

• 1 Just make foo.js a module that exports functions. Then in main file var foo = require('./extras/foo'); – bryanmac Commented Mar 2, 2014 at 0:05
• 1 nodejs/api/modules.html – bryanmac Commented Mar 2, 2014 at 0:06
• so if other functions call the main.js, how would they use the submodule of main called foo? – Cmag Commented Mar 2, 2014 at 0:07

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 7

If you want main.js to basically duplicate and enhance everything foo has (which is silly, but that seems to be what you are asking), you can do this:

main.js

var foo = require('./extras/foo');
for (var prop in foo) {
  exports[prop] = foo[prop];
}
exports.fdsa = function(...
exports.asdf = function(...

./extras/foo.js

exports.foo = function(...

Side note if you put a file in somedir/index.js, it can be required as just somedir, which can also be useful.

If you just want access to foo by way of main and are OK with a sub-namespace, just do:

main.js

exports.foo = require('./extras/foo');

Then your calling code can do:

require('./main').foo.foo(blah, callback);

Also note if you want the entire foo module to be a function, just do:

module.exports = function foo(barf, callback) {...

There is a much simple way to achieve this with es6 module pattern. So in foo.js

export function foo(barf, callback) {
     ...
     callback(err, result);
}

And in main.js you will have something like,

export * from './foo.js';
export function fdsa(barf, callback) {
...
}