I am trying to bine two javascript
functions into one function.
So, I have this chunk of code:
<form name="form1" action="testing_page2.php" method="GET">
<p><input id="Main" type="checkbox" name="Main" value="1" onClick="javascript:uncheckSecondary(this);" />Main</p>
<p><input id="Secondary" type="checkbox" name="Secondary" value="2" />Secondary</p>
</form>
<script language="javascript" type="text/javascript">
function uncheckSecondary(obj)
{
if (obj.checked == true)
{
document.getElementById("Secondary").checked = false;
}
}
</script>
Here, when the page loads, the Secondary checkbox will be checked (I have an if clause
there, but it is not related to my question) , but Main is not checked.
As I check the Main checkbox, Secondary is unchecked.
And also I have another piece of code:
<script language="javascript">
function checkRefresh(value)
{
document.form1.submit();
}
</script>
<form name="form1" action="testing_page2.php" method="GET">
<p><input id="Main" type="checkbox" name="Main" value="1" onClick="this.form.submit();"/>Main</p>
<p><input id="Secondary" type="checkbox" name="Secondary" value="2" onClick="this.form.submit();"/>Secondary</p>
</form>
Here, as I check/uncheck any of checkboxes, the form is submitted.
Edited:
What I want is to bine function checkRefresh(value)
and function uncheckSecondary(obj)
, so that when I check Main, the Secondary is unchecked and form is submitted, and vice versa.
I am trying to bine two javascript
functions into one function.
So, I have this chunk of code:
<form name="form1" action="testing_page2.php" method="GET">
<p><input id="Main" type="checkbox" name="Main" value="1" onClick="javascript:uncheckSecondary(this);" />Main</p>
<p><input id="Secondary" type="checkbox" name="Secondary" value="2" />Secondary</p>
</form>
<script language="javascript" type="text/javascript">
function uncheckSecondary(obj)
{
if (obj.checked == true)
{
document.getElementById("Secondary").checked = false;
}
}
</script>
Here, when the page loads, the Secondary checkbox will be checked (I have an if clause
there, but it is not related to my question) , but Main is not checked.
As I check the Main checkbox, Secondary is unchecked.
And also I have another piece of code:
<script language="javascript">
function checkRefresh(value)
{
document.form1.submit();
}
</script>
<form name="form1" action="testing_page2.php" method="GET">
<p><input id="Main" type="checkbox" name="Main" value="1" onClick="this.form.submit();"/>Main</p>
<p><input id="Secondary" type="checkbox" name="Secondary" value="2" onClick="this.form.submit();"/>Secondary</p>
</form>
Here, as I check/uncheck any of checkboxes, the form is submitted.
Edited:
What I want is to bine function checkRefresh(value)
and function uncheckSecondary(obj)
, so that when I check Main, the Secondary is unchecked and form is submitted, and vice versa.
- Try the new code i just added... – Luigi Siri Commented Apr 19, 2013 at 14:23
2 Answers
Reset to default 2Try this piece of code...
<script>
function checkRefresh(value)
{
document.form1.submit();
}
function uncheck(check)
{
var prim = document.getElementById("Main");
var secn = document.getElementById("Secondary");
if (prim.checked == true && secn.checked == true)
{
if(check == 1)
{
secn.checked = false;
checkRefresh();
}
else if(check == 2)
{
prim.checked = false;
checkRefresh();
}
}
}
</script>
<form name="form1" action="#" method="POST">
<p><input id="Main" type="checkbox" name="Main" value="1" onClick="uncheck(1);"/>Main</p>
<p><input id="Secondary" type="checkbox" name="Secondary" value="2" onClick="uncheck(2)"/>Secondary</p>
</form>
It will submit the form only when the condition applies as you stated.
Wele to Javascript.
<form name="form1" action="#" method="POST">
<p><input id="Main" type="checkbox" name="Main" value="1" onClick="if (this.checked) document.getElementById('Secondary').checked = false; this.form.submit();"/>Main</p>
<p><input id="Secondary" type="checkbox" name="Secondary" value="2" onClick=""/>Secondary</p>
</form>
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