I'm trying to get an array of all elements with the class "sampleclass". For example, withing my document I have three divs:
<div class="aclass"></div>
<div class="sampleclass"></div>
<div class="anotheraclass"></div>
<div class="sampleclass"></div>
I want to get an array with all elements that are within the "sampleclass" using javascipt and/or jQuery.
Any ideas on how to do this?
I'm trying to get an array of all elements with the class "sampleclass". For example, withing my document I have three divs:
<div class="aclass"></div>
<div class="sampleclass"></div>
<div class="anotheraclass"></div>
<div class="sampleclass"></div>
I want to get an array with all elements that are within the "sampleclass" using javascipt and/or jQuery.
Any ideas on how to do this?
Share Improve this question edited Mar 29, 2010 at 11:14 Péter Török 116k31 gold badges277 silver badges331 bronze badges asked Mar 29, 2010 at 11:12 Tomas VinterTomas Vinter 2,6919 gold badges36 silver badges45 bronze badges 2- 1 Just to clarify - which browsers do you need to support? JQuery should support most, some DOM methods dont work across the board. – Russell Commented Mar 29, 2010 at 11:16
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You want all the elements INSIDE the
sampleclass
element? If yes then there is a typo in the question, and most people have answered wrong. – Alex Bagnolini Commented Mar 29, 2010 at 11:17
4 Answers
Reset to default 3This will get all the elements inside each element containing the sampleclass
class:
var myArray = $('.sampleclass *');
*
is called the All selector
EDIT: please note, in this example:
<div id="test">
<table>
<tr><td>TEST</td></tr>
</table>
</div>
var myArray = $('#test *');
myArray
contains all the sub-elements of the div: table
, tr
and td
.
If you want all the top-level elements inside a given element, you can try:
var myArray = $('#test > *');
This bines the child selector with the aforementioned all selector.
$( '.sampleclass' );
You can then iterate through the array with each
.
......
$('.sampleclass').........
Further you can iterate over it using each
like this:
$('.sampleclass').each(function(){
// more code........
})
And finally, you can get each individual item like this too:
$('.sampleclass')[0]; // first
$('.sampleclass')[1]; // second
// and so on........
Expanding Jacob Relkin' answer:
$('.sampleClass').each(function()
{
// do something with it...
$(this).css('background-color', 'green');
});
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