var RegTxt =  "$f1$='test' AND f2='test2'";
alert(RegTxt.match(/\'[^\']*'/g))

returns the match correctely i:e 'test','test2' but how can i remove the single quote in the match.

var RegTxt =  "$f1$='test' AND f2='test2'";
alert(RegTxt.match(/\'[^\']*'/g))

returns the match correctely i:e 'test','test2' but how can i remove the single quote in the match.

• javascript
• regex

Share Improve this question Follow edited Apr 6, 2010 at 14:22 skaffman 404k9696 gold badges824824 silver badges775775 bronze badges asked Apr 6, 2010 at 14:20 mushtaqmushtaq 1111 silver badge22 bronze badges

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4 Answers 4

Sorted by: Reset to default 3

This would be quite simple if JavaScript supported negative lookbehinds:

/(?<=').*?(?=')/

But unfortunately, it doesn't.

In cases like these I like to abuse String.prototype.replace:

// btw, RegTxt should start with a lowercase 'r', as per convention
var match = [];
regTxt.replace(/'([^']*)'/g, function($0, $1){
    match.push($1);
});
match; // => ['test', 'test2']

Here is a crude solution to your problem.

var match = RegTxt.match(/\'[^\']*'/g)
match = match.substring(1, match.length - 2);

Trivial approach:

RegTxt.replace(/'/g, "")

using your regex:

RegTxt.replace(/\'([^\']*)'/g, "$1")

var matches = str.match(regex);
var newMatches = [];
for( i in matches )
{
var word = matches[i];
newMatches.push( word.substring(1,word.length-1))
}

newMatches will now contain the array you need.