javascript - How to combine 2 or more observables so that you know which emitted? - Stack Overflow

let's say you have 2 observables:const obs1$: Observable<string[]> = this.getObs1$();const

let's say you have 2 observables:

const obs1$: Observable<string[]> = this.getObs1$();
const obs2$: Observable<string[]> = this.getObs2$();

i want to bine these 2 so that in subscription (or rxjs map) i know which emitted the values. I can't use bineLatest because for the other observable i just get the latest value it emitted at some point.

let's say you have 2 observables:

const obs1$: Observable<string[]> = this.getObs1$();
const obs2$: Observable<string[]> = this.getObs2$();

i want to bine these 2 so that in subscription (or rxjs map) i know which emitted the values. I can't use bineLatest because for the other observable i just get the latest value it emitted at some point.

Share Improve this question asked Jan 29, 2022 at 7:16 char mchar m 8,34618 gold badges73 silver badges129 bronze badges 3
  • Can't you add type for each observable? Something like this one: stackoverflow./questions/45455763/… – Alon Shmiel Commented Jan 29, 2022 at 8:01
  • 2 You can chain each Observable with map() and wrap it with some data strucutre that you can use to identify the source. – martin Commented Jan 29, 2022 at 18:29
  • this is what i did – char m Commented Feb 2, 2022 at 15:50
Add a ment  | 

3 Answers 3

Reset to default 2

There doesn't seem to be a purely RxJS solution to this (but hopefully someone can prove me wrong on that!)

You could use a variable in the outter scope to track the emitting observable as a workaround

let trigger: TriggerEnum;

const obs1$: Observable<string[]> = this.getObs1$()
  .pipe(tap(() => trigger = TriggerEnum.One));
const obs2$: Observable<string[]> = this.getObs2$()
  .pipe(tap(() => trigger = TriggerEnum.Two));;

bineLatest(....).subscribe(
 // check trigger value
);

From the docs as a just-in-case: be aware that bineLatest will not emit an initial value until each observable emits at least one value

You can use merge to bine the two observables into a single observable. Then, do what @martin suggested and map each source's emissions to a little structure that allows you identify the source:

const obs1$: Observable<number[]> = getNumbers();
const obs2$: Observable<string[]> = getLetters();

const bined$ = merge(
  obs1$.pipe(map(data => ({ source: 'obs1$', data }))), 
  obs2$.pipe(map(data => ({ source: 'obs2$', data })))
);

bined$.subscribe(
   ({ source, data }) => console.log(`[${source}] data: ${data}`)
);

// OUTPUT:
//
// [obs1$] data: 1
// [obs2$] data: A
// [obs2$] data: A,B
// [obs2$] data: A,B,C
// [obs1$] data: 1,2
// [obs2$] data: A,B,C,D
...

Here's a little StackBlitz example.

I didn't get what I needed out of merge but my go-to is bineLatestWith

this.transaction$
  .pipe(takeUntil(this._ngUnsubscribe), 
  bineLatestWith(this.selectedStatus$)) // ngxs add latest sliced data to response
  .subscribe(([status, tx]) => {
    console.log(status, tx);
  });

With NGXS its convenient to attach one of your slices via selector to also get the data in the response.

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