hi i have following JSON objects;

var obj1 = {"a":1,"b":1,"c":1};
var obj2 = {"a":2,"b":2,"c":2};
var obj3 = {"a":3,"b":3,"c":3};

i want to sum,or subtract above 3 json Objects i want final result as

  {"a":6,"b":6,"c":6}

i know it is very simple by using different types of loop. but i want to know whether is there any function exists in javascript to merge multiple JSON objects and add or subtract each properties(without loop).

is there possible like reduce function in array: like below:

var squares = arr.concat(arr2).reduce((t,n)=>t+n);

Thanks

hi i have following JSON objects;

var obj1 = {"a":1,"b":1,"c":1};
var obj2 = {"a":2,"b":2,"c":2};
var obj3 = {"a":3,"b":3,"c":3};

i want to sum,or subtract above 3 json Objects i want final result as

  {"a":6,"b":6,"c":6}

i know it is very simple by using different types of loop. but i want to know whether is there any function exists in javascript to merge multiple JSON objects and add or subtract each properties(without loop).

is there possible like reduce function in array: like below:

var squares = arr.concat(arr2).reduce((t,n)=>t+n);

Thanks

• javascript
• jquery
• object

Share Improve this question Follow edited Nov 28, 2018 at 11:09 cнŝdk 32.2k77 gold badges6060 silver badges8080 bronze badges asked Nov 28, 2018 at 10:58 ghanshyam.miranighanshyam.mirani 3,1111111 gold badges4949 silver badges8686 bronze badges 3

• 5 ,'c'=1} is invalid syntax... – CertainPerformance Commented Nov 28, 2018 at 10:59
• invalid syntax! – mahradbt Commented Nov 28, 2018 at 11:00
• 1 this is just example of json object having key value pair – ghanshyam.mirani Commented Nov 28, 2018 at 11:01

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 6

There's no such built-in function that can acplish something like that automatically, but it's trivial to write your own code that does what you want:

var obj1 = {"a":1,"b":1,'c':1};
var obj2 = {"a":2,"b":2,'c':2};
var obj3 = {"a":3,"b":3,'c':3};
const bined = [obj1, obj2, obj3].reduce((a, obj) => {
  Object.entries(obj).forEach(([key, val]) => {
    a[key] = (a[key] || 0) + val;
  });
  return a;
});
console.log(bined);

You can just loop over one of your object properties and construct the result:

let res = {};
for (p in obj1) {
  res[p] = obj1[p] + (obj2[p] || 0) + (obj3[p] || 0);
}

Demo:

var obj1 = {"a":1,"b":1,"c":1};
var obj2 = {"a":2,"b":2,"c":2};
var obj3 = {"a":3,"b":3,"c":3};

let res = {};

for (p in obj1) {
  res[p] = obj1[p] + (obj2[p] || 0) + (obj3[p] || 0);
}
console.log(res);