Write a function named "sort_by_average" that takes a list/array of key-value stores as a parameter where each key-value store has keys "ratings", "budget", and "box_office" where budget and box_office are integers and ratings is a list of integers. Sort the input based on the average of the values in "ratings"

function sort_by_average(lista){
    for(var i of lista){
        lista.sort(i.ratings.reduce/i.ratings.length);
    }
    return lista;
}

I am getting TypeError: The parison function must be either a function or undefined. How can I fix this?

Write a function named "sort_by_average" that takes a list/array of key-value stores as a parameter where each key-value store has keys "ratings", "budget", and "box_office" where budget and box_office are integers and ratings is a list of integers. Sort the input based on the average of the values in "ratings"

function sort_by_average(lista){
    for(var i of lista){
        lista.sort(i.ratings.reduce/i.ratings.length);
    }
    return lista;
}

I am getting TypeError: The parison function must be either a function or undefined. How can I fix this?

• javascript
• algorithm

Share Improve this question Follow asked Nov 14, 2018 at 15:45 user10649535user10649535 1

• Hello mate, the Array.protoytype.sort() requires a function as parameter or undefined, that's why you encounter TypeError. You also don't have to loop through the list to sort it, you can take a look at the example provided in the link above. – ptdien Commented Nov 14, 2018 at 15:54

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1 Answer 1

Sorted by: Reset to default 2

If pareFunction is supplied, all non-undefined array elements are sorted according to the return value of the pare function (all undefined elements are sorted to the end of the array, with no call to pareFunction).

So you have to create a function like this and pass it to sort():

function pare(a, b) {
  if (a is less than b by some ordering criterion) {
    return -1;
  }
  if (a is greater than b by the ordering criterion) {
    return 1;
  }
  // a must be equal to b
  return 0;
}

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