Check password strength using javascriptjquery - Stack Overflow

I am looking to implement a password strength feature for my textbox in my asp website.Currently, my c

I am looking to implement a password strength feature for my textbox in my asp website.

Currently, my code looks like this:

<span id="password_strength"></span>
<script type="text/javascript">
    function CheckPasswordStrength(password) {
        var password_strength = document.getElementById("password_strength");

        //if textBox is empty
        if(password.length==0){
            password_strength.innerHTML = "";
            return;
        }

        //Regular Expressions
        var regex = new Array();
        regex.push("[A-Z]"); //For Uppercase Alphabet
        regex.push("[a-z]"); //For Lowercase Alphabet
        regex.push("[0-9]"); //For Numeric Digits
        regex.push("[$@$!%*#?&]"); //For Special Characters

        var passed = 0;

        //Validation for each Regular Expression
        for (var i = 0; i < regex.length; i++) {
            if(new RegExp (regex[i]).test(password){
                passed++;
            }
        }

        //Validation for Length of Password
        if(passed > 2 && password.length > 8){
            passed++;
        }

        //Display of Status
        var color = "";
        var passwordStrength = "";
        switch(passed){
            case 0:
            case 1:
                passwordStrength = "Password is Weak.";
                color = "Red";
                break;
            case 2:
                passwordStrength = "Password is Good.";
                color = "darkorange";
                break;
            case 3:
            case 4:
                passwordStrength = "Password is Strong.";
                color = "Green";
                break;
            case 5:
                passwordStrength = "Password is Very Strong.";
                color = "darkgreen";
                break;
        }
        password_strength.innerHTML = passwordStrength;
        password_strength.style.color = color;
    }
</script>

<div class="row">
    <div class="col-sm-6">
        <center><asp:label runat="server" text="Password :" Font-Bold="True" Font-Italic="False"></asp:label></center>
        <center><asp:TextBox ID="tbPassword" runat="server" onkeyup="CheckPasswordStrength(this.value)"></asp:TextBox></center>
    </div>
</div>

I found this code online. I tried it on my website and it does not work. I would really appreciate if somebody can help me with my code.

I am looking to implement a password strength feature for my textbox in my asp website.

Currently, my code looks like this:

<span id="password_strength"></span>
<script type="text/javascript">
    function CheckPasswordStrength(password) {
        var password_strength = document.getElementById("password_strength");

        //if textBox is empty
        if(password.length==0){
            password_strength.innerHTML = "";
            return;
        }

        //Regular Expressions
        var regex = new Array();
        regex.push("[A-Z]"); //For Uppercase Alphabet
        regex.push("[a-z]"); //For Lowercase Alphabet
        regex.push("[0-9]"); //For Numeric Digits
        regex.push("[$@$!%*#?&]"); //For Special Characters

        var passed = 0;

        //Validation for each Regular Expression
        for (var i = 0; i < regex.length; i++) {
            if(new RegExp (regex[i]).test(password){
                passed++;
            }
        }

        //Validation for Length of Password
        if(passed > 2 && password.length > 8){
            passed++;
        }

        //Display of Status
        var color = "";
        var passwordStrength = "";
        switch(passed){
            case 0:
            case 1:
                passwordStrength = "Password is Weak.";
                color = "Red";
                break;
            case 2:
                passwordStrength = "Password is Good.";
                color = "darkorange";
                break;
            case 3:
            case 4:
                passwordStrength = "Password is Strong.";
                color = "Green";
                break;
            case 5:
                passwordStrength = "Password is Very Strong.";
                color = "darkgreen";
                break;
        }
        password_strength.innerHTML = passwordStrength;
        password_strength.style.color = color;
    }
</script>

<div class="row">
    <div class="col-sm-6">
        <center><asp:label runat="server" text="Password :" Font-Bold="True" Font-Italic="False"></asp:label></center>
        <center><asp:TextBox ID="tbPassword" runat="server" onkeyup="CheckPasswordStrength(this.value)"></asp:TextBox></center>
    </div>
</div>

I found this code online. I tried it on my website and it does not work. I would really appreciate if somebody can help me with my code.

Share Improve this question edited Sep 12, 2022 at 8:21 Mark Rotteveel 110k229 gold badges156 silver badges224 bronze badges asked Aug 5, 2016 at 1:26 MrStutterzMrStutterz 591 silver badge8 bronze badges 2
  • Wele to Stack Overflow! Please have a read over stackoverflow./help/how-to-ask for assistance in asking the right types of questions. I'd suggest with this example above asking something specific. The way it's worded now sounds like you're asking us to do research and find issues in your code snippet that you didn't write, and solve it for you. You should be able to ask a specific question first. – mariocatch Commented Aug 5, 2016 at 2:07
  • I have no idea what "does not work" means. Describe exact behavior. What is it doing, which line of code does it deviate from what you expect? – mason Commented Aug 5, 2016 at 2:25
Add a ment  | 

1 Answer 1

Reset to default 5

Add break into case 3 and case 0. Then set default after case 5.

http://www.w3schools./js/js_switch.asp

EDIT:

I updated your function

 function CheckPasswordStrength(password) {
  var password_strength = document.getElementById("password_strength");


    //if textBox is empty
    if(password.length==0){
        password_strength.innerHTML = "";
        return;
    }

    //Regular Expressions
    var regex = new Array();
    regex.push("[A-Z]"); //For Uppercase Alphabet
    regex.push("[a-z]"); //For Lowercase Alphabet
    regex.push("[0-9]"); //For Numeric Digits
    regex.push("[$@$!%*#?&]"); //For Special Characters

    var passed = 0;

    //Validation for each Regular Expression
    for (var i = 0; i < regex.length; i++) {
        if((new RegExp (regex[i])).test(password)){
            passed++;
        }
    }

    //Validation for Length of Password
    if(passed > 2 && password.length > 8){
        passed++;
    }

    //Display of Status
    var color = "";
    var passwordStrength = "";
    switch(passed){
        case 0:
            break;
        case 1:
            passwordStrength = "Password is Weak.";
            color = "Red";
            break;
        case 2:
            passwordStrength = "Password is Good.";
            color = "darkorange";
            break;
        case 3:
                break;
        case 4:
            passwordStrength = "Password is Strong.";
            color = "Green";
            break;
        case 5:
            passwordStrength = "Password is Very Strong.";
            color = "darkgreen";
            break;
    }
    password_strength.innerHTML = passwordStrength;
    password_strength.style.color = color;
}

Test: https://jsfiddle/Lko29h8m/1/

发布者:admin,转转请注明出处:http://www.yc00.com/questions/1744983797a4604492.html

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