I was initially trying to do this:

var array = ['A','B','C'];
array = _.each(array, function(item) { return item + '+' });

to get this:

['A+','B+','C+'];

but _.each does not seem to return a function.

I eventually settled on this:

var array = ['A','B','C'];
newArray = [];
_.each(array, function(item) {
  newArray.push(item + '+');
});

but it seems pretty clunky by parison.

Am I using _.each incorrectly, or is there another function I should be using?

I was initially trying to do this:

var array = ['A','B','C'];
array = _.each(array, function(item) { return item + '+' });

to get this:

['A+','B+','C+'];

but _.each does not seem to return a function.

I eventually settled on this:

var array = ['A','B','C'];
newArray = [];
_.each(array, function(item) {
  newArray.push(item + '+');
});

but it seems pretty clunky by parison.

Am I using _.each incorrectly, or is there another function I should be using?

• javascript
• underscore.js
• lodash

Share Follow asked Oct 3, 2013 at 0:43 Klatch BaldarKlatch Baldar 5988 bronze badges 1

• 1 use _.map to return an array - _.each is just an iterator method – kinakuta Commented Oct 3, 2013 at 0:46

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 6

is there another function I should be using?

Yes. each never returns an array, it just iterates. Use map to produce an array of callback results.

var array = _.map(['A','B','C'], function(item) { return item + '+' });

Making my ment an answer instead - use _.map to return an array. The _.each method will simply iterate through your collection.

var newArray = _.map(array, function(item) {
  return item + '+';
});