I have "222 22 222", "333 33 33 333", "1234/34", and "ab345 543" and I want to check whether these inputs are numeric and white space. I.E this case, the first and the second inputs should return True by using method Test of Regular Expression, or return its own value by using Exec method. The third and the fourth should return false. How could I do so in Regular Expression? Please help. Thank you.

I have "222 22 222", "333 33 33 333", "1234/34", and "ab345 543" and I want to check whether these inputs are numeric and white space. I.E this case, the first and the second inputs should return True by using method Test of Regular Expression, or return its own value by using Exec method. The third and the fourth should return false. How could I do so in Regular Expression? Please help. Thank you.

• javascript
• regex
• numbers

Share Improve this question Follow edited Sep 7, 2010 at 8:19 kennytm 524k110110 gold badges1.1k1.1k silver badges1k1k bronze badges asked Sep 7, 2010 at 8:10 VicheanakVicheanak 6,7042020 gold badges6767 silver badges9999 bronze badges 4

• What language or tool are you using? Regular expressions have slightly different syntax in different languages. – Mark Byers Commented Sep 7, 2010 at 8:13
• sorry. I used Javascript – Vicheanak Commented Sep 7, 2010 at 8:16
• 1 What results would you expect for " " and "1234". ie All whitespaces and all numerics ? – El Ronnoco Commented Sep 7, 2010 at 8:33
• i would expect it to return 222 22 222, 333 33 33 333 the same as I have input. But the third and the fourth won't return anything or return false. – Vicheanak Commented Sep 7, 2010 at 8:36

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3 Answers 3

Sorted by: Reset to default 7

You can test with this regular expression:

/^[\d\s]+$/

Rubular

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If you want to also check that there is at least one digit in the string:

/^\s*\d[\d\s]*$/

You can use something like this regex: ^(?:[0-9]|\s)*$

Here's a test case in python:

test=["222 22 222", "333 33 33 333", "1234/34","ab345 543"]
for i in test:
    m = re.match("^(?:[0-9]|\s)*$", i)
    if (m == None): print("False")
    else: print("True: %s" % m.group())

The resut is:

True: 222 22 222
True: 333 33 33 333
False
False

Cheers Andrea

I think it should be something like [\d\s{0,1}]