Is console.log() supposed to print out the value of a variable at the time it's called in your JavaScript? That was my assumption but when I run the code below in either Firefox (using Firebug) or Google Chrome (and use the built-in dev tools), I seem to get the "final" value of an array rather than the value of the array at that time. If I use alert() statements they print out what I would expect - the value of an array at the time the alert() statement is called.
var params = new Array();
var tmp = new Array('apple', 'banana', 'cat');
for (var i=0; i < tmp.length; i++) {
params[tmp[i]] = [];
}
console.log(params);
/*
SHOWS IN CONSOLE:
- []
+ apple ["jan", "feb", "mar", "apr"]
+ banana ["jan", "feb", "mar", "apr"]
+ apple ["jan", "feb", "mar", "apr"]
*/
alert( print_arr(params) );
/*
ALERT BOX TEXT:
[apple]:
[banana]:
[cat]:
*/
console.log('===========================================');
var tmp2 = new Array('jan', 'feb', 'mar', 'apr');
for (var i=0; i < tmp.length; i++) {
for (var j=0; j < tmp2.length; j++) {
params[tmp[i]].push(tmp2[j]);
}
}
console.log(params);
/*
SHOWS IN CONSOLE:
- []
+ apple ["jan", "feb", "mar", "apr"]
+ banana ["jan", "feb", "mar", "apr"]
+ apple ["jan", "feb", "mar", "apr"]
*/
alert( print_arr(params) );
/*
ALERT BOX TEXT:
[apple]:jan,feb,mar,apr
[banana]:jan,feb,mar,apr
[cat]:jan,feb,mar,apr
*/
function print_arr(arr) {
var str = '';
for (var k in arr) {
str += '[' + k + ']:' + arr[k].toString() + "\n";
}
return str;
}
Is console.log() supposed to print out the value of a variable at the time it's called in your JavaScript? That was my assumption but when I run the code below in either Firefox (using Firebug) or Google Chrome (and use the built-in dev tools), I seem to get the "final" value of an array rather than the value of the array at that time. If I use alert() statements they print out what I would expect - the value of an array at the time the alert() statement is called.
var params = new Array();
var tmp = new Array('apple', 'banana', 'cat');
for (var i=0; i < tmp.length; i++) {
params[tmp[i]] = [];
}
console.log(params);
/*
SHOWS IN CONSOLE:
- []
+ apple ["jan", "feb", "mar", "apr"]
+ banana ["jan", "feb", "mar", "apr"]
+ apple ["jan", "feb", "mar", "apr"]
*/
alert( print_arr(params) );
/*
ALERT BOX TEXT:
[apple]:
[banana]:
[cat]:
*/
console.log('===========================================');
var tmp2 = new Array('jan', 'feb', 'mar', 'apr');
for (var i=0; i < tmp.length; i++) {
for (var j=0; j < tmp2.length; j++) {
params[tmp[i]].push(tmp2[j]);
}
}
console.log(params);
/*
SHOWS IN CONSOLE:
- []
+ apple ["jan", "feb", "mar", "apr"]
+ banana ["jan", "feb", "mar", "apr"]
+ apple ["jan", "feb", "mar", "apr"]
*/
alert( print_arr(params) );
/*
ALERT BOX TEXT:
[apple]:jan,feb,mar,apr
[banana]:jan,feb,mar,apr
[cat]:jan,feb,mar,apr
*/
function print_arr(arr) {
var str = '';
for (var k in arr) {
str += '[' + k + ']:' + arr[k].toString() + "\n";
}
return str;
}
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asked Mar 20, 2013 at 15:47
BillBill
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6
- 2 console logs the object, so any changes made to the object will get reflected in the logged objet – Arun P Johny Commented Mar 20, 2013 at 15:49
-
3
console.log(JSON.stringify(yourObj));
- try that instead. – James Allardice Commented Mar 20, 2013 at 15:50 - Why do you create an array and fill it with properties instead of values? Why not use Object instead? – newtover Commented Mar 20, 2013 at 15:53
-
A small ment on your coding style: Do not use new
Array(a,b,c)
but[a,b,c]
. It is easier on the eyes and the identifier does not have to be looked up. – Kijewski Commented Mar 20, 2013 at 15:53 - Is Chrome's JavaScript console lazy about evaluating arrays? – Andreas Commented Mar 20, 2013 at 15:54
1 Answer
Reset to default 8As I said in the ments console.log(obj)
does not log a string representation, it logs a reference to the actual javascript object in the memory. So any changes made to the object will get reflected in the logged instance.
If you want to trace the progressive changes made, then convert the object to a string and print to like console.log(JSON.stringify(params))
.
Also you are not using params
as an array, you are using it as an map. so change params
to an object var params = {}
Change params
to an object and use JSON.stringify
to log it
var params = {};
var tmp = new Array('apple', 'banana', 'cat');
for (var i=0; i < tmp.length; i++) {
params[tmp[i]] = [];
}
console.log(JSON.stringify(params));
/*
SHOWS IN CONSOLE:
- []
+ apple ["jan", "feb", "mar", "apr"]
+ banana ["jan", "feb", "mar", "apr"]
+ apple ["jan", "feb", "mar", "apr"]
*/
alert( print_arr(params) );
/*
ALERT BOX TEXT:
[apple]:
[banana]:
[cat]:
*/
console.log('===========================================');
var tmp2 = new Array('jan', 'feb', 'mar', 'apr');
for (var i=0; i < tmp.length; i++) {
for (var j=0; j < tmp2.length; j++) {
params[tmp[i]].push(tmp2[j]);
}
}
console.log(JSON.stringify(params));
/*
SHOWS IN CONSOLE:
- []
+ apple ["jan", "feb", "mar", "apr"]
+ banana ["jan", "feb", "mar", "apr"]
+ apple ["jan", "feb", "mar", "apr"]
*/
alert( print_arr(params) );
/*
ALERT BOX TEXT:
[apple]:jan,feb,mar,apr
[banana]:jan,feb,mar,apr
[cat]:jan,feb,mar,apr
*/
function print_arr(arr) {
var str = '';
for (var k in arr) {
str += '[' + k + ']:' + arr[k].toString() + "\n";
}
return str;
}
Demo: Fiddle
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