when i add two numbers in javascript.e.g.,

var a = 4.0;
var b = 4.0;
var c = a+b;

When i print sum in console it gives 8, but i want 8.0, so i did this,

console.log(c.toFixed(1));

and when i checked

console.log(typeof c);

it gives output as string. The problem is that i want output as number and with a decimal place. Even the parseFloat() function did not help.

Overall what i want:

//input
a=4.0;
b=4.0;

//output
a+b = 8.0;

when i add two numbers in javascript.e.g.,

var a = 4.0;
var b = 4.0;
var c = a+b;

When i print sum in console it gives 8, but i want 8.0, so i did this,

console.log(c.toFixed(1));

and when i checked

console.log(typeof c);

it gives output as string. The problem is that i want output as number and with a decimal place. Even the parseFloat() function did not help.

Overall what i want:

//input
a=4.0;
b=4.0;

//output
a+b = 8.0;

• javascript

Share Improve this question Follow asked Sep 4, 2017 at 11:41 AnimayAnimay 63011 gold badge77 silver badges1818 bronze badges 9

• 8 8.0 is 8 as a number ... if you want 8.0 you can only have 8.0 as a string - javascript doesn't "know" you want 1 decimal ... what if you wanted 8.00, would it have to store that differently to 8.0? – Jaromanda X Commented Sep 4, 2017 at 11:43
• A number has as many decimal places as you want - it only matters when you turn it into a string. – Evan Knowles Commented Sep 4, 2017 at 11:43
• typeof(c) gives you string? – James Thorpe Commented Sep 4, 2017 at 11:44
• console.log(8 === 8.0) – baao Commented Sep 4, 2017 at 11:44
• where do you want a number with places? – Nina Scholz Commented Sep 4, 2017 at 11:44

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2 Answers 2

Sorted by: Reset to default 4

Try parseFloat() with toFixed()

var a = 4.0;
var b = 4.0;
var c = a+b;
console.log(parseFloat(c).toFixed(1)); -- 8.0
console.log(typeof c); -- number

toFixed retuns a string. And it have to returns a string because this is only way you have to output something like 8.0.

If you try console.log(8.0), you'll get 8. This is how the console output works and you can't really go against it.