everyone.
I have a problem about the 'callback function - scope of variable',
I wanna use the 'i in for loop' to 'the callback function User_UidSearch',
but I cannot use it.
(I hope the solution don't use the global variable.)
Task_TidSearchExecution = function(tid, callback) {
var sql = "SELECT * FROM execution WHERE task = '" + tid + "'";
dbclient.query(sql, function (err, results) {
if (err || results.length <= 0)
callback(false);
else {
console.log(results.length);
for (var i = 0 ; i < results.length ; i++) {
User_UidSearch(results[i].employee, function (user) {
console.log(i);
// results[i]['email'] = user.email;
});
}
callback(results);
}
});
}
the "console.log(i);"
Recheck, this is wrong. -> Outputs are "undefined" of all.
undefined is "console.log(result[i]);"
But the "i" is keep '2' console twice, if results.length is 2.
I know becuz the for loop ending then execute the User_UidSearch,
but how can I slove the it "i" is 0 and 1.
everyone.
I have a problem about the 'callback function - scope of variable',
I wanna use the 'i in for loop' to 'the callback function User_UidSearch',
but I cannot use it.
(I hope the solution don't use the global variable.)
Task_TidSearchExecution = function(tid, callback) {
var sql = "SELECT * FROM execution WHERE task = '" + tid + "'";
dbclient.query(sql, function (err, results) {
if (err || results.length <= 0)
callback(false);
else {
console.log(results.length);
for (var i = 0 ; i < results.length ; i++) {
User_UidSearch(results[i].employee, function (user) {
console.log(i);
// results[i]['email'] = user.email;
});
}
callback(results);
}
});
}
the "console.log(i);"
Recheck, this is wrong. -> Outputs are "undefined" of all.
undefined is "console.log(result[i]);"
But the "i" is keep '2' console twice, if results.length is 2.
I know becuz the for loop ending then execute the User_UidSearch,
but how can I slove the it "i" is 0 and 1.
Share Improve this question edited Aug 13, 2014 at 8:02 Salmon asked Aug 13, 2014 at 7:48 SalmonSalmon 1333 silver badges11 bronze badges 6-
No, it's not. It's defined in outer
function
local scope. But it's used in closure, which needs special logic to work. @Salmon - are you sureconsole.log(i)
writesundefined
and not the value ofresults.length
? – Ilya Luzyanin Commented Aug 13, 2014 at 7:55 - @BOSS I would love to see a fiddle demonstrating that. – Robby Cornelissen Commented Aug 13, 2014 at 7:56
-
1
"Outputs are 'undefined' of all" doesn't really fit with the snippet provided.
i
should at least be a number, just maybe not the particular values expected. If each log shows the value ofresults.length
, then see: JavaScript closure inside loops – simple practical example. – Jonathan Lonowski Commented Aug 13, 2014 at 7:56 - wrap the user_UidSearch call in a closure, pass in i and results – MartinWebb Commented Aug 13, 2014 at 7:57
- @IlyaLuzyanin: rigt.my bad i didnt see it through clearly.removed my ment – Prabhu Murthy Commented Aug 13, 2014 at 7:58
2 Answers
Reset to default 3Your problem may be solved, but let me still add these points so others know the correct approach.
Firstly, its not a good practice to call an asynchronous function inside a loop. This would lead to unexpected results.
Using closures is fine for some cases, but not this one. Read here for Practical uses of closures.
There are several problems in the approach you've taken,
- If the results array is too long, there'll be a too many open requests.
callback(results)
will be called before even a single callback ofUser_UidSearch
is called.
In your case, you should be using recursive function like this:
var len = results.length;
var count = 0;
function my_func() {
User_UidSearch(results[count].employee, function (user) {
console.log(count);
// results[count]['email'] = user.email;
count += 1;
if (count < len) {
my_func();
} else {
callback(results);
}
});
}
Read this if interested detailed explaination of different control flows.
You're dealing with closures, rewrite your code as follows:
...
(function(id) {
User_UidSearch(results[id].employee, function (user) {
console.log(id);
// results[i]['email'] = user.email;
});
})(i);
I.e. wrap your function to unbind i
.
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