I have a regular expression which validates 3 consecutive digits.

/^\d{3}$/.test("12345")  // false
/^\d{3}$/.test("123")    // true

How can I transform this regex pattern into a RegExp object?

I tried:

var re = new RegExp("\\d{3}", "gi");

but re.test("12345") returns true

What am I doing wrong?

I have a regular expression which validates 3 consecutive digits.

/^\d{3}$/.test("12345")  // false
/^\d{3}$/.test("123")    // true

How can I transform this regex pattern into a RegExp object?

I tried:

var re = new RegExp("\\d{3}", "gi");

but re.test("12345") returns true

What am I doing wrong?

• javascript
• regex

Share Improve this question Follow edited Jan 30, 2012 at 7:53 James Allardice 166k2222 gold badges334334 silver badges315315 bronze badges asked Jan 30, 2012 at 7:48 CatalinCatalin 11.7k1919 gold badges8080 silver badges152152 bronze badges

Add a ment  | 

4 Answers 4

Sorted by: Reset to default 5

var re = new RegExp("^\\d{3}$", "gi");

(I assume the "gi" flag is not really necessary in this case...)

http://jsfiddle/GyZqw/

new RegExp("^\\d{3}$", "gi")

you forgot ^ and $

Use this regular expression:

^\d{3}$

with start and end of line specified.

In JavaScript you should escape \ char, i.e.:

"^\\d{3}$"

var re = new RegExp("^\\d{3}$");