I'm using this example for a D3.js tree layout.

.html

I need to flip it, so the root node is on the right hand side, and the links... etc.

How can I achieve this?

I'm using this example for a D3.js tree layout.

http://mbostock.github./d3/talk/20111018/tree.html

I need to flip it, so the root node is on the right hand side, and the links... etc.

How can I achieve this?

• javascript
• json
• svg
• d3.js

Share Improve this question Follow asked Mar 27, 2013 at 23:12 user1277546user1277546 8,78233 gold badges1919 silver badges2626 bronze badges 1

• possible duplicate of Tree drawing orientation – Ian Commented Feb 9, 2015 at 15:47

Add a ment  | 

1 Answer 1

Sorted by: Reset to default 8

• Change the offset of each node to be from the right rather than offset from the left:

  // Normalize for fixed-depth.
  nodes.forEach(function(d) { d.y = d.depth * 180; });
  

Bees:

    // Normalize for fixed-depth from right.
    nodes.forEach(function(d) { d.y = w - (d.depth * 180); });

• Change the labels to be on the opposite sides

  nodeEnter.append("svg:text")
    .attr("x", function(d) { return d.children || d._children ? -10 : 10; })
    .attr("dy", ".35em")
    .attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })    
    .text(function(d) { return d.name; })
    .style("fill-opacity", 1e-6);
  

Bees:

    nodeEnter.append("svg:text")
      .attr("x", function(d) { return d.children || d._children ? 10 : -10; })
      .attr("dy", ".35em")
      .attr("text-anchor", function(d) { return d.children || d._children ? "start" : "end"; })    
      .text(function(d) { return d.name; })
      .style("fill-opacity", 1e-6);

• Make original position of the root node on the right hand side, rather than the left so first transition isn't weird:

  root = json;
  root.x0 = h / 2;
  root.y0 = 0;
  

Bees:

    root = json;
    root.x0 = h / 2;
    root.y0 = w;

Fiddle: http://jsfiddle/Ak5tP/1/embedded/result/