Consider the following code:

new Promise(function (res, rej) {
    res('a','b')
}).then(function (a, b) {
    console.log(a,b)
})

It outputs

a undefined

How can I resolve return the two values out of the Promise?

Consider the following code:

new Promise(function (res, rej) {
    res('a','b')
}).then(function (a, b) {
    console.log(a,b)
})

It outputs

a undefined

How can I resolve return the two values out of the Promise?

• javascript
• node.js
• asynchronous
• promise

Share Improve this question Follow asked Aug 31, 2018 at 13:54 TSRTSR 20.8k3232 gold badges120120 silver badges240240 bronze badges 2

• 2 With an array ? – Luca Kiebel Commented Aug 31, 2018 at 13:55
• or object... ;-) – Lyubomir Commented Aug 31, 2018 at 13:56

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3 Answers 3

Sorted by: Reset to default 6

Return them in an array.

new Promise((res, rej) => {
  res(["a", "b"]);
}).then(([a, b]) => {
  console.log(a, b);
});

You cannot, a promise fulfills or rejects with exactly one value.

It's trivial however to put the two values in a structure, such as an array:

new Promise(function(resolve) {
    resolve(['a','b'])
}).then(function([a, b]) { // array destructuring
    console.log(a, b)
})

new Promise(function (res, rej) {
    res(['a','b'])
}).then(function (resContent) {
    console.log(...resContent)
})

It outputs

a b