I'm designing a report with a JSON data source (groovy language).

My JSON looks like this:

{
  ...
  "moreIds": [
    {
      "code": "OB4442735001",
      "codScheme": "CLIENT_REF"
    },
    {
      "code": "setr.010",
      "codScheme": "INITIAL_SWIFT_TYPE"
    },
    ...
  ],
  ...
}

I want to extract the code value for a given codScheme value (say "CLIENT_REF") from the moreIds array.

Initially I tried to extract the value in a field as follows:

<field name="orderClientRef" class="java.lang.String">
    <property name="net.sf.jasperreports.json.field.expression" value="moreIds.find{it.codScheme=='CLIENT_REF'}.code"/>
</field>

This doesn't work, it yields an empty value. I tried a bunch of other variations of the expression, but without success.

In the end this is what I did that worked:

I defined a field containing the full moreIds array:

<field name="moreIds" class="java.lang.Object">
    <property name="net.sf.jasperreports.json.field.expression" value="moreIds"/>
</field>

I used the following expression in the text field:

$F{moreIds}.find{it.get("codScheme").textValue()=="CLIENT_REF"}.get("code").textValue()

While it does achieve the goal, I find it less than elegant, and I'd like to know if there is a more elegant way to do this.

I'm designing a report with a JSON data source (groovy language).

My JSON looks like this:

{
  ...
  "moreIds": [
    {
      "code": "OB4442735001",
      "codScheme": "CLIENT_REF"
    },
    {
      "code": "setr.010",
      "codScheme": "INITIAL_SWIFT_TYPE"
    },
    ...
  ],
  ...
}

I want to extract the code value for a given codScheme value (say "CLIENT_REF") from the moreIds array.

Initially I tried to extract the value in a field as follows:

<field name="orderClientRef" class="java.lang.String">
    <property name="net.sf.jasperreports.json.field.expression" value="moreIds.find{it.codScheme=='CLIENT_REF'}.code"/>
</field>

This doesn't work, it yields an empty value. I tried a bunch of other variations of the expression, but without success.

In the end this is what I did that worked:

I defined a field containing the full moreIds array:

<field name="moreIds" class="java.lang.Object">
    <property name="net.sf.jasperreports.json.field.expression" value="moreIds"/>
</field>

I used the following expression in the text field:

$F{moreIds}.find{it.get("codScheme").textValue()=="CLIENT_REF"}.get("code").textValue()

While it does achieve the goal, I find it less than elegant, and I'd like to know if there is a more elegant way to do this.

• json
• groovy
• jasper-reports
• jaspersoft-studio

Share Improve this question Follow asked Mar 25 at 14:15 Olivier GérardinOlivier Gérardin 1,2451616 silver badges3131 bronze badges

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1 Answer 1

Sorted by: Reset to default 1

I suspect that net.sf.jasperreports.json.field.expression only wants a field name, and hence it's not happy with a full Groovy expression like that.

It seems like their JSON parser isn't the typical JsonSlurper from Groovy so your syntax you posted would have issues. However, you might simpilfy things (if it's a Groovy Expression) like so:

// working expression
$F{moreIds}.find{it.get("codScheme").textValue()=="CLIENT_REF"}.get("code").textValue()
// get is just the method name for [] operator so you could remove that using:
$F{moreIds).find(it["codScheme"].textValue()=="CLIENT_REF"}["code"]?.textValue()
// and dot notation could work if this is Groovy:
$F{moreIds).find(it.codScheme.textValue()=="CLIENT_REF"}?.code?.textValue()

I added the ?. operator so if things were null it wouldn't blow up and just gracefully return null.

I think you may look into JSONQL for what you are doing and that might be more elegant in one statement rather than selecting JSON and then applying Groovy Statement.

https://jasperreports.sourcefe/sample.reference/jsonqldatasource/README.html