I am new to node js. I was trying to create a simple HTTP server. I followed the famous example and created a 'Hello World!' server as follows.

var handleRequest = function(req, res) {
  res.writeHead(200);
  res1.end('Hello, World!\n');
};

require('http').createServer(handleRequest).listen(8080);

console.log('Server started on port 8080');

Running this code would start the server properly as expected. But trying to access http://127.0.0.1:8080 would crash it by throwing an error that res1 is not defined. I would like to have the server still continue running and gracefully report errors whenever it encounters it.

How do I achieve it? I tried try-catch but that isn't helping me :(

I am new to node js. I was trying to create a simple HTTP server. I followed the famous example and created a 'Hello World!' server as follows.

var handleRequest = function(req, res) {
  res.writeHead(200);
  res1.end('Hello, World!\n');
};

require('http').createServer(handleRequest).listen(8080);

console.log('Server started on port 8080');

Running this code would start the server properly as expected. But trying to access http://127.0.0.1:8080 would crash it by throwing an error that res1 is not defined. I would like to have the server still continue running and gracefully report errors whenever it encounters it.

How do I achieve it? I tried try-catch but that isn't helping me :(

• javascript
• node.js
• webserver

Share Improve this question Follow edited Jan 13, 2013 at 17:48 Goje87 asked Jan 13, 2013 at 17:21 Goje87Goje87 2,86977 gold badges3030 silver badges4949 bronze badges 2

• 2 See stackoverflow./a/8114990/435413 (autoreboot javascript) or stackoverflow./questions/5999373/… (prevent crash) – sod Commented Jan 13, 2013 at 18:01
• 1 Hi Benjamin, I purposefully typed it as res1 to generate error. My question is about how to handle such errors without crashing the server. – Goje87 Commented Jan 13, 2013 at 18:45

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 6

There are a bunch of ments here. First of all, for your example server to work, handleRequest needs to be defined BEFORE using it.

1- What you actually want, which is preventing the process to exit, can be handled by handling uncaughtException (documentation) event:

var handleRequest = function(req, res) {
    res.writeHead(200);
    res1.end('Hello, World!\n');
};
var server = require('http').createServer(handleRequest);
process.on('uncaughtException', function(ex) {
    // do something with exception
});
server.listen(8080);
console.log('Server started on port 8080');

2- I would rement to use try{} catch(e) {} on your code, such as:

var handleRequest = function(req, res) {
    try {
      res.writeHead(200);
      res1.end('Hello, World!\n');
    } catch(e) {
      res.writeHead(200);
      res.end('Boo');
    }
};

3- I guess the example was just an example and not actual code, this is a parsing error that can be prevented. I mention this, since you NEED to NOT have parsing errors on Exception catch handlers.

4- Please note that node process is going to be replaced in the future with domain

5- I'd rather use a framework like express, than doing this stuff.

6- Remended lecture: StackOverflow - NodeJS best practice for exception handling

I am not targeting your question details but your question's title about preventing Node server from crashing. You can probably use DOMAIN, this will probably stop your server from crashing when an uncaughtException is thrown.

domain = require('domain'),
d = domain.create();

d.on('error', function(err) {
  console.error(err);
});

for more details go http://shapeshed./uncaught-exceptions-in-node/

beside using this method must try-catch your block.

Maybe you should define handleRequest before you use it:

require('http').createServer(handleRequest).listen(8080);

function handleRequest(req, res) {
  res.writeHead(200);
  res1.end('Hello, World!\n');
};

Or

var handleRequest = function(req, res) {
  res.writeHead(200);
  res1.end('Hello, World!\n');
};

require('http').createServer(handleRequest).listen(8080);

---

And you should be sure that res1 also exists.