I was wondering if there is any way to skip key in object loop. If I have:

obj = {
   key1 : [ 1, 2, 3 ],
   key2 : [ 4, 5 ],
   key3 : []
}

how can I skip, for example, the empty one. Because I want to join() the not empty arrays in that object, and filter them. If I join that empty array the filter looks for empty string and of course it doesn't find it, and everything brakes.

var match = $('.widget');
for ( var i in obj ){
    var joined = obj[i].join();
    match = match.filter(joined);
}

I have tried to delete it:

if ( obj[i].length == 0 ) {
    delete obj[i]
};

but error occurs that obj[i] is undefined and can't join it. How can I just skip it.

I was wondering if there is any way to skip key in object loop. If I have:

obj = {
   key1 : [ 1, 2, 3 ],
   key2 : [ 4, 5 ],
   key3 : []
}

how can I skip, for example, the empty one. Because I want to join() the not empty arrays in that object, and filter them. If I join that empty array the filter looks for empty string and of course it doesn't find it, and everything brakes.

var match = $('.widget');
for ( var i in obj ){
    var joined = obj[i].join();
    match = match.filter(joined);
}

I have tried to delete it:

if ( obj[i].length == 0 ) {
    delete obj[i]
};

but error occurs that obj[i] is undefined and can't join it. How can I just skip it.

• javascript
• jquery

Share Improve this question Follow edited Jan 28, 2013 at 18:58 Панайот Толев asked Jan 28, 2013 at 18:56 Панайот ТолевПанайот Толев 6,60755 gold badges2121 silver badges2828 bronze badges

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2 Answers 2

Sorted by: Reset to default 12

Use loop control:

for (var i in obj) {
   if (obj[i].length == 0) {
       continue;
   }
   ...
}

You need to pass the key to delete a property :

for ( var i in obj ){
    if ( obj[i].length == 0 ) {
        delete i
    }
}