I need to convert an array or an array of arrays to an object with keys named from an array of names. Example:

//given names
    names = ['first', 'second', 'third', 'fourth'] 
//array
    param = [1, 2, 3, 4] 
//bees 
    result = {first: 1, second: 2, third: 3, fourth: 4}

//array of arrays 
    param = [
      [1, 2, 3, 4],
      [-4, 3, 1, 32],
    ]
//bees
    result = [
      {first: 1, second: 2, third: 3, fourth: 4},
      {first: -4, second: 3, third: 1, fourth: 32},
    ]

My current solution is this:

    var names = ['first', 'second', 'third', 'forth'];

    function arrayToObject(array, names) {
      var result = {};
      for (var i = 0; i < array.length; i++) {
        if (typeof array[i] === 'object') {
          result[i] = arrayToObject(array[i], names);
          continue;
        }
        result[names[i]] = array[i];
      }
      return result;
    }

The problem with this solution is that it always returns an object, though it should return an array of objects when I pass in an array of arrays. Is there a way to do this with lodash and I'm not seeing it?

I need to convert an array or an array of arrays to an object with keys named from an array of names. Example:

//given names
    names = ['first', 'second', 'third', 'fourth'] 
//array
    param = [1, 2, 3, 4] 
//bees 
    result = {first: 1, second: 2, third: 3, fourth: 4}

//array of arrays 
    param = [
      [1, 2, 3, 4],
      [-4, 3, 1, 32],
    ]
//bees
    result = [
      {first: 1, second: 2, third: 3, fourth: 4},
      {first: -4, second: 3, third: 1, fourth: 32},
    ]

My current solution is this:

    var names = ['first', 'second', 'third', 'forth'];

    function arrayToObject(array, names) {
      var result = {};
      for (var i = 0; i < array.length; i++) {
        if (typeof array[i] === 'object') {
          result[i] = arrayToObject(array[i], names);
          continue;
        }
        result[names[i]] = array[i];
      }
      return result;
    }

The problem with this solution is that it always returns an object, though it should return an array of objects when I pass in an array of arrays. Is there a way to do this with lodash and I'm not seeing it?

• javascript
• arrays
• object
• lodash

Share Improve this question Follow edited Mar 18, 2016 at 12:02 Kek asked Mar 18, 2016 at 11:56 KekKek 2311 gold badge22 silver badges55 bronze badges 5

• you mismatch copy and result. copy is not declared. – Alexey Obukhov Commented Mar 18, 2016 at 12:01
• Fixed it, forgot to rename it – Kek Commented Mar 18, 2016 at 12:03
• then it is ok. you declare result as object. write if statement: result = [] if array, result = {} if hash – Alexey Obukhov Commented Mar 18, 2016 at 12:03
• Thanks, I knew that. That's why I'm asking for something like a lodash solution, for it to be as concise as possible :) – Kek Commented Mar 18, 2016 at 12:11
• As I mentioned below, _.zipObject() is concise. – Mr. Polywhirl Commented Mar 18, 2016 at 12:17

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 7

Vanilla JS: A function that creates an object from an array:

function toObj(arr) {
  return arr.reduce(function(p, c, i) {
    p[names[i]] = c;
    return p;
  }, {});
}

Used with map:

var out = arr.map(toObj);

DEMO

You can use _.zipObject() to zip up two arrays into an object. You are essentially mapping CSV data, with headers, to JavaScript objects.

You can try to search for JavaScript CSV converters. You may find some interesting results.

// Given names
var names = [ 'first', 'second', 'third', 'fourth' ]; 
// Array
var param = [ 1, 2, 3, 4 ];
// Bees 
var result = _.zipObject(names, param);

document.body.innerHTML = JSON.stringify(result, null, 2);

// Array of arrays 
var param = [
  [ 1, 2, 3, 4 ],
  [ -4, 3, 1, 32 ],
];
// Bees
var result = _.chain(param).map(function(p) {
	return _.zipObject(names, p)
}).value();

document.body.innerHTML += '\n\n' + JSON.stringify(result, null, 2);

body {
  font-family: monospace;
  white-space: pre;
}

<script src="https://cdnjs.cloudflare./ajax/libs/lodash.js/4.6.1/lodash.min.js"></script>