The lazy plugin works fine for the initially loaded elements but doesn't work for images loaded via AJAX despite having the code in done function of the AJAX call.

Here is my code for lazy loading images

jQuery(document).ready(function() {
    jQuery("img.lazy").lazy({
        effect: "fadeIn",
        effectTime: 1000
    });
});

Here is my AJAX call

$(document).ready(function() {
    $('#loadmore-dj').on('click', function() {
        $('#loadmore-dj').hide();
        $('#loadmore-dj-gif').css( "display", "block");
        $.ajax({
            type: "GET",
            url: "/loadmore/dj/",
            data: {
                'slug': $('.dj_slug').text().trim(),
                'song_rank': $("#dj_song_list").find('.song_block').length
            },
        }).done(function (response) {
            $(response).appendTo($('#dj_song_list')).hide().fadeIn(1000);
            playOneAudio();
            jQuery(document).ready(function() {
                jQuery("img.lazy").lazy({
                    effect: "fadeIn",
                    effectTime: 1000
                });
            });
            $('#loadmore-dj').show();
            $('#loadmore-dj-gif').hide();
        }).done(hideLoadMore);
    });
});

The lazy plugin works fine for the initially loaded elements but doesn't work for images loaded via AJAX despite having the code in done function of the AJAX call.

Here is my code for lazy loading images

jQuery(document).ready(function() {
    jQuery("img.lazy").lazy({
        effect: "fadeIn",
        effectTime: 1000
    });
});

Here is my AJAX call

$(document).ready(function() {
    $('#loadmore-dj').on('click', function() {
        $('#loadmore-dj').hide();
        $('#loadmore-dj-gif').css( "display", "block");
        $.ajax({
            type: "GET",
            url: "/loadmore/dj/",
            data: {
                'slug': $('.dj_slug').text().trim(),
                'song_rank': $("#dj_song_list").find('.song_block').length
            },
        }).done(function (response) {
            $(response).appendTo($('#dj_song_list')).hide().fadeIn(1000);
            playOneAudio();
            jQuery(document).ready(function() {
                jQuery("img.lazy").lazy({
                    effect: "fadeIn",
                    effectTime: 1000
                });
            });
            $('#loadmore-dj').show();
            $('#loadmore-dj-gif').hide();
        }).done(hideLoadMore);
    });
});

• javascript
• jquery
• ajax
• lazy-loading
• jquery-lazyload

Share Improve this question Follow edited Aug 14, 2014 at 5:05 Yin Yang asked Aug 13, 2014 at 20:26 Yin YangYin Yang 1,80633 gold badges2828 silver badges4848 bronze badges 2

• Remove the inner jQuery(document).ready(function() {...}) wrapper from your .done callback; it's not needed. – Blazemonger Commented Aug 13, 2014 at 20:53
• Is this the plugin? jquery.eisbehr.de/lazy – Blazemonger Commented Aug 13, 2014 at 21:19

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2 Answers 2

Sorted by: Reset to default 9

The problem was the missing scroll-event on the AJAX load with lazy by default. Adding the config parameter bind: "event" to lazy in my ajax function solved the issue.

jQuery("img.lazy").lazy({
    effect: "fadeIn",
    effectTime: 1000,
    bind: "event"
});

Your .lazy plugin is called before the fadeIn is plete. Try this --

    }).done(function (response) {
        $(response).appendTo($('#dj_song_list')).hide().fadeIn(1000, function() {
            playOneAudio();
            jQuery("img.lazy").lazy({ // don't need document.ready twice
                effect: "fadeIn",
                effectTime: 1000
            });
            $('#loadmore-dj').show();
            $('#loadmore-dj-gif').hide();
            hideLoadMore(); // don't need two .done() callbacks.
        });
    });