First, I want parse a html and fetch some line

with Google Apps Script, and it's showed

" The element type "link" must be terminated by the matching end-tag "/link " "

and code here

var response = UrlFetchApp.fetch(url)
var downloadContent = response.getContentText();
var doc = XmlService.parse(downloadContent);

I think because the html use html5, that GAS can't parsing,

---

so I try otherwise method to parsing string, (read line by line and keep lines which I need)

var xml = UrlFetchApp.fetch(url).getContentText();

but GAS hasn't Scanner, and how can I do?

---

In fact, I want to go this url ".html"

and fetch information in

<div class="r-ent">
...
</div>

First, I want parse a html and fetch some line

with Google Apps Script, and it's showed

" The element type "link" must be terminated by the matching end-tag "/link " "

and code here

var response = UrlFetchApp.fetch(url)
var downloadContent = response.getContentText();
var doc = XmlService.parse(downloadContent);

I think because the html use html5, that GAS can't parsing,

---

so I try otherwise method to parsing string, (read line by line and keep lines which I need)

var xml = UrlFetchApp.fetch(url).getContentText();

but GAS hasn't Scanner, and how can I do?

---

In fact, I want to go this url "https://www.ptt/bbs/gossiping/index.html"

and fetch information in

<div class="r-ent">
...
</div>

• javascript
• html
• parsing
• google-apps-script
• fetch

Share Improve this question Follow asked Jun 8, 2017 at 9:51 JimmyHoJimmyHo 28911 gold badge55 silver badges1414 bronze badges 2

• You might find Spencer Easton's new library useful for parsing HTML: github./Spencer-Easton/Apps-Script-htmlparser2-library – Andrew Roberts Commented Jun 8, 2017 at 12:23
• I will follow this git, thanks! @AndrewRoberts – JimmyHo Commented Jun 9, 2017 at 4:01

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1 Answer 1

Sorted by: Reset to default 9

Google Apps Script is JavaScript so you can use the split() method to split the text content into multiple lines by the newline character.

var text = UrlFetchApp.fetch(url).getContentText();
var lines = text.split(/\r?\n/);
Logger.log(lines);