can somebody tell me what is wrong?

JS Code

$.ajax({
    url:"",
    success:function(data){

        var test_data = ''+data+''; // convert object to a string
        $('body').append(typeof(test_data));

        var test_data = replace.test_data(/[0-9]/,'X');
        $('body').append('<hr />'+test_data+' <hr />');

    },
    dataType:'jsonp',
    error:function(){
        alert('error');
    }
});

jsfiddle /

Thanks in advance!
Peter

can somebody tell me what is wrong?

JS Code

$.ajax({
    url:"http://www.google.com/complete/search?qu=chicken",
    success:function(data){

        var test_data = ''+data+''; // convert object to a string
        $('body').append(typeof(test_data));

        var test_data = replace.test_data(/[0-9]/,'X');
        $('body').append('<hr />'+test_data+' <hr />');

    },
    dataType:'jsonp',
    error:function(){
        alert('error');
    }
});

jsfiddle http://www.jsfiddle.net/V9Euk/664/

Thanks in advance!
Peter

• javascript

Share Improve this question Follow asked Oct 10, 2010 at 16:37 PeterPeter 11.8k3131 gold badges101101 silver badges154154 bronze badges 1

• get your hand on a good debugger like: getfirebug.com – gblazex Commented Oct 10, 2010 at 16:46

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3 Answers 3

Sorted by: Reset to default 11

You got it backwards; it should be

test_data.replace(...);

Also, you don't need var before the second assignment to "test_data"; just the first one.

replace is undefined. It is not an object.

Use replace from the string prototype

"string".replace(//, "");

As you can see:

alert(String.prototype.replace)

Results in

function replace() {
    [native code]
}

You should replace replace.test_data by test_data.replace