Let say I have foo(). Is there a way to execute bar() after foo() without modifying foo()?
foo(){ /* logic */}
bar(){ /* more logic *}
afterEvent1AlwaysExecute2(foo,bar);
Any non-jQuery or jQuery ments are appreciated :)
Let say I have foo(). Is there a way to execute bar() after foo() without modifying foo()?
foo(){ /* logic */}
bar(){ /* more logic *}
afterEvent1AlwaysExecute2(foo,bar);
Any non-jQuery or jQuery ments are appreciated :)
Share Improve this question edited Nov 17, 2022 at 23:10 Brian Tompsett - 汤莱恩 5,89372 gold badges61 silver badges133 bronze badges asked Jul 19, 2012 at 1:09 jdpubjdpub 312 bronze badges 1-
You could always wrap
fooinside a new function which will call the oldfoo, and then callbar. Then you change the name of this new function tofoo. As far as the outside world is concernedfooshould work as expected, but secretly your replaced implementation will also callbar. Win! – Anurag Commented Jul 19, 2012 at 1:14
1 Answer
Reset to default 9You can do it without adding code to foo, by reassigning the name foo:
var original_foo = foo;
var foo = function() { original_foo(); bar(); }
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