I have a string like (12.131883, -68.84942999999998) and with using .replace() I wish to remove the brackets, or get the values between the brackets. A simple latlon = latlon.replace('(',' '') is not working.

Also tried it with latlon.replace(/\(.*?\)\s/g, '') but no luck.

Can anyone help me out here?

I have a string like (12.131883, -68.84942999999998) and with using .replace() I wish to remove the brackets, or get the values between the brackets. A simple latlon = latlon.replace('(',' '') is not working.

Also tried it with latlon.replace(/\(.*?\)\s/g, '') but no luck.

Can anyone help me out here?

• javascript
• jquery

Share Improve this question Follow asked Oct 9, 2015 at 20:07 Alvin BakkerAlvin Bakker 1,53611 gold badge2121 silver badges4141 bronze badges 5

• How is "(12.131883, -68.84942999999998)".replace('(', ''); not working ? Any error ? I just tried it in the console and it works just fine.. – Nico Commented Oct 9, 2015 at 20:10
• 2 Use substr, var str = '(12.131883, -68.84942999999998)'; str.substr(1, str.length -2); – Tushar Commented Oct 9, 2015 at 20:13
• 1 OR str.replace(/\(|\)/g, '') OR str.replace(/[()]/g, '') OR str.match(/[^()]/g); Choose whichever you like – Tushar Commented Oct 9, 2015 at 20:19
• Tushar, many thanx. Something this stupid I overlooked. – Alvin Bakker Commented Oct 9, 2015 at 20:27
• @AlvinBakker Glad to help :) – Tushar Commented Oct 9, 2015 at 20:31

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2 Answers 2

Sorted by: Reset to default 4

You can use substring:

var myString = "(12.131883, -68.84942999999998)";
var latlong = myString.substring(1, myString.indexOf(')'));

Or:

var myString = "(12.131883, -68.84942999999998)";
var latlong = myString.substring(myString.indexOf('(') + 1, myString.indexOf(')'));

You can get them in an array with:

var latlon = "(12.131883, -68.84942999999998)";
var ll = latlon.match(/[-+]?[0-9]*\.?[0-9]+/g)
console.log(ll) // returns ["12.131883", "-68.84942999999998"]