I have 2 arrays of Objects;

// First one :
[0: {id: 1},
1: {id: 2},
2: {id: 3},
3: {id: 4}]

// Second one :
[0: {id: 10},
1: {id: 1},
2: {id: 4},
3: {id: 76},
4: {id: 2},
5: {id: 47},
6: {id: 3}]

I'd like to test if the second one has at least every same IDs of the first one. Which would be true in this case because the second one contains 1, 2, 3 and 4 IDs.

I tried to use some() and every() but it doesn't work properly

My try :

let res = this.trainingEpisodesList.some( episode => {
    thispletedEpisodes.every( userEpisode => {
         userEpisode.id == episode.id;
     })
});

Thanks ;)

I have 2 arrays of Objects;

// First one :
[0: {id: 1},
1: {id: 2},
2: {id: 3},
3: {id: 4}]

// Second one :
[0: {id: 10},
1: {id: 1},
2: {id: 4},
3: {id: 76},
4: {id: 2},
5: {id: 47},
6: {id: 3}]

I'd like to test if the second one has at least every same IDs of the first one. Which would be true in this case because the second one contains 1, 2, 3 and 4 IDs.

I tried to use some() and every() but it doesn't work properly

My try :

let res = this.trainingEpisodesList.some( episode => {
    this.pletedEpisodes.every( userEpisode => {
         userEpisode.id == episode.id;
     })
});

Thanks ;)

• javascript
• arrays
• object
• foreach
• verification

Share Improve this question Follow edited Aug 30, 2020 at 20:47 arhak 2,55211 gold badge2727 silver badges3939 bronze badges asked Aug 30, 2020 at 18:05 Lu DoLu Do 9711 silver badge99 bronze badges 2

• but it doesn't work properly is not an error description. What is your expectation and what is the output of your code? – Jens Commented Aug 30, 2020 at 18:08
• Not returning anything inside of a some or every call is one reason, why your try won't do what you want. I'd also get a better IDE/linter (or configure them properly), a statement like userEpisode.id == episode.id; should be automatically marked as "probably a mistake". – ASDFGerte Commented Aug 30, 2020 at 18:15

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 4

ES7,

let result = one.map(a => a.id);
let result2 = two.map(a => a.id);
const final_result = result.every(val => result2.includes(val));

ES5,

var result = one.map(a => a.id);
var result2 = two.map(a => a.id);

var final_result = result.every(function(val) {

  return result2.indexOf(val) >= 0;

});

You can do this using every and find:

let pletedEpisodes = 
[
{id: 1},
{id: 2},
{id: 3},
{id: 4}
]

let trainingEpisodesList = 
[
{id: 10},
{id: 1},
{id: 4},
{id: 76},
{id: 2},
{id: 47},
{id: 3}
]

let containsAllCompleted = trainingEpisodesList.every(c => pletedEpisodes.find(e=>e.id==c.id));

console.log(containsAllCompleted);