2024年4月24日发(作者：)

IF ischar = FALSE THEN

raise_application_error(-20003, 'Password should contain at least one

digit, one character and one punctuation');

END IF;

-- 3. Check for the punctuation

<>

ispunct:=FALSE;

FOR i IN 1..length(punctarray) LOOP

FOR j LOOP

IF substr(password,j,1) = substr(punctarray,i,1) THEN

ispunct:=TRUE;

GOTO endsearch;

END IF;

END LOOP;

END LOOP;

IF ispunct = FALSE THEN

raise_application_error(-20003, 'Password should contain at least one

digit, one character and one punctuation');

END IF;

<>

-- Check if the password differs from the previous password by at least

-- 3 letters

IF old_password IS NOT NULL THEN

differ := length(old_password) - length(password);

IF abs(differ) < 3 THEN

IF length(password) < length(old_password) THEN

m := length(password);

ELSE

m := length(old_password);

END IF;

differ := abs(differ);

FOR i LOOP

IF substr(password,i,1) != substr(old_password,i,1) THEN

differ := differ + 1;

END IF;

END LOOP;

IF differ < 3 THEN

raise_application_error(-20004, 'Password should differ by at

least 3 characters');

END IF;

END IF;

END IF;

-- Everything is fine; return TRUE ;

RETURN(TRUE);

END;

CREATE OR REPLACE FUNCTION verify_function_11G

(username varchar2,

password varchar2,

old_password varchar2)

RETURN boolean IS

n boolean;

m integer;

differ integer;

isdigit boolean;

ischar boolean;

ispunct boolean;

db_name varchar2(40);

digitarray varchar2(20);

punctarray varchar2(25);

chararray varchar2(52);

i_char varchar2(10);

simple_password varchar2(10);

reverse_user varchar2(32);

BEGIN

digitarray:= '';

chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';

-- Check for the minimum length of the password

IF length(password) < 8 THEN

raise_application_error(-20001, 'Password length less than 8');

END IF;

-- Check if the password is same as the username or username(1-100)

IF NLS_LOWER(password) = NLS_LOWER(username) THEN

raise_application_error(-20002, 'Password same as or similar to user');

END IF;

FOR i IN 1..100 LOOP

i_char := to_char(i);

if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN

raise_application_error(-20005, 'Password same as or similar to user name ');

END IF;

END LOOP;

-- Check if the password is same as the username reversed

FOR i in REVERSE 1..length(username) LOOP

reverse_user := reverse_user || substr(username, i, 1);

END LOOP;

IF NLS_LOWER(password) = NLS_LOWER(reverse_user) THEN

raise_application_error(-20003, 'Password same as username reversed');

END IF;

-- Check if the password is the same as server name and or servername(1-100)

select name into db_name from sys.v$database;

if NLS_LOWER(db_name) = NLS_LOWER(password) THEN

raise_application_error(-20004, 'Password same as or similar to server name');

END IF;

FOR i IN 1..100 LOOP

i_char := to_char(i);

if NLS_LOWER(db_name)|| i_char = NLS_LOWER(password) THEN

raise_application_error(-20005, 'Password same as or similar to server name ');

END IF;

END LOOP;

-- Check if the password is too simple. A dictionary of words may be

-- maintained and a check may be made so as not to allow the words

-- that are too simple for the password.

IF NLS_LOWER(password) IN ('welcome1', 'database1', 'account1', 'user1234', 'password1', 'oracle123', 'computer1', 'abcdefg1', 'change_on_install') THEN

raise_application_error(-20006, 'Password too simple');

END IF;

-- Check if the password is the same as oracle (1-100)

simple_password := 'oracle';

FOR i IN 1..100 LOOP

i_char := to_char(i);

if simple_password || i_char = NLS_LOWER(password) THEN

raise_application_error(-20007, 'Password too simple ');

END IF;

END LOOP;

-- Check if the password contains at least one letter, one digit

-- 1. Check for the digit

isdigit:=FALSE;

m := length(password);

FOR i IN 1..10 LOOP

FOR j LOOP

IF substr(password,j,1) = substr(digitarray,i,1) THEN

isdigit:=TRUE;

GOTO findchar;

END IF;

END LOOP;

END LOOP;

IF isdigit = FALSE THEN

raise_application_error(-20008, 'Password must contain at least one digit, one character');

END IF;

-- 2. Check for the character

<>

ischar:=FALSE;

FOR i IN 1..length(chararray) LOOP

FOR j LOOP

IF substr(password,j,1) = substr(chararray,i,1) THEN

ischar:=TRUE;

GOTO endsearch;

END IF;

END LOOP;

END LOOP;

IF ischar = FALSE THEN

raise_application_error(-20009, 'Password must contain at least one

digit, and one character');

END IF;

<>

-- Check if the password differs from the previous password by at least

-- 3 letters

IF old_password IS NOT NULL THEN

differ := length(old_password) - length(password);

differ := abs(differ);

IF differ < 3 THEN

IF length(password) < length(old_password) THEN

m := length(password);

ELSE

m := length(old_password);

END IF;

FOR i LOOP

IF substr(password,i,1) != substr(old_password,i,1) THEN

differ := differ + 1;

END IF;

END LOOP;

IF differ < 3 THEN

raise_application_error(-20011, 'Password should differ from the

old password by at least 3 characters');

END IF;

END IF;

END IF;

-- Everything is fine; return TRUE ;

RETURN(TRUE);

END;

5.设置密码策略

SQL> alter system set resource_limit = true;

SQL> alter profile default limit password_verify_function verify_function;

6.查看密码策略是否设置成功

SQL> select * from dba_profiles where resource_NAME='PASSWORD_VERIFY_FUNCTION';