python樱花代码_使用python图形模块turtle库绘制樱花、玫瑰、圣诞树代码

python樱花代码_使用python图形模块turtle库绘制樱花、玫瑰、圣诞树代码


2024年1月23日发(作者:)

代码from turtle import *from random import *from math import *def tree(n, l):pd()t = cos(radians(heading() + 45)) / 8 + 0.25pencolor(t, t, t)pensize(n / 4)forward(l)if n > 0:b = random() * 15 + 10c = random() * 15 + 10d = l * (random() * 0.35 + 0.6)right(b)tree(n - 1, d)left(b + c)tree(n - 1, d)right(c)else:right(90)

n = cos(radians(heading() - 45)) / 4 + 0.5pencolor(n, n, n)circle(2)left(90)pu()backward(l)bgcolor(0.5, 0.5, 0.5)ht()speed(0)tracer(0, 0)left(90)pu()backward(300)tree(13, 100)done()Python绘制玫瑰花代码实例效果(有绘制过程)代码from turtle import *

import timesetup(1000,800,0,0)speed(0)penup()seth(90)fd(340)seth(0)pendown()speed(5)begin_fill()fillcolor('red')circle(50,30)for i in range(10):fd(1)left(10)circle(40,40)for i in range(6):fd(1)left(3)circle(80,40)for i in range(20):fd(0.5)left(5)circle(80,45)for i in range(10):fd(2)left(1)circle(80,25)for i in range(20):fd(1)left(4)circle(50,50)(0.1)circle(120,55)

speed(0)seth(-90)fd(70)right(150)fd(20)left(140)circle(140,90)left(30)circle(160,100)left(130)fd(25)penup()right(150)circle(40,80)pendown()left(115)fd(60)penup()left(180)fd(60)pendown()end_fill()right(120)circle(-50,50)circle(-20,90)speed(1)fd(75)speed(0)circle(90,110)penup()left(162)fd(185)left(170)pendown()

circle(200,10)circle(100,40)circle(-52,115)left(20)circle(100,20)circle(300,20)speed(1)fd(250)penup()speed(0)left(180)fd(250)circle(-300,7)right(80)circle(200,5)pendown()left(60)begin_fill()fillcolor('green')circle(-80,100)right(90)fd(10)left(20)circle(-63,127)end_fill()penup()left(50)fd(20)left(180)pendown()circle(200,25)penup()right(150)fd(180)

from turtle import *import randomimport timen = 100.0speed("fastest")screensize(bg='seashell')left(90)forward(3*n)color("orange", "yellow")begin_fill()left(126)for i in range(5):forward(n/5)right(144)forward(n/5)left(72)end_fill()right(126)color("dark green")backward(n*4.8)def tree(d, s):if d <= 0: returnforward(s)tree(d-1, s*.8)right(120)tree(d-3, s*.5)right(120)tree(d-3, s*.5)right(120)backward(s)tree(15, n)backward(n/2)for i in range(200):a = 200 - 400 * ()


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