2048python代码

2048python代码


2024年1月18日发(作者:)

2048python代码

以下是使用Python语言编写的2048游戏代码:

```python

import random

# 创建游戏棋盘

def create_board():

board = [[0] * 4 for _ in range(4)]

return board

# 在棋盘上随机生成一个新的数字

def generate_number(board):

empty_cells = [(i, j) for i in range(4) for j in range(4)

if board[i][j] == 0]

if empty_cells:

row, col = (empty_cells)

board[row][col] = ([2, 4])

# 显示游戏界面

def display_board(board):

for row in board:

for cell in row:

print(f"{cell:4}", end="")

print()

# 移动棋盘上的数字

def move(board, direction):

if direction == "up":

board = transpose(board)

board = slide(board)

board = transpose(board)

elif direction == "down":

board = transpose(board)

board = reverse(board)

board = slide(board)

board = reverse(board)

board = transpose(board)

elif direction == "left":

board = slide(board)

elif direction == "right":

board = reverse(board)

board = slide(board)

board = reverse(board)

return board

# 将棋盘转置

def transpose(board):

return [list(row) for row in zip(*board)]

# 将棋盘逆序

def reverse(board):

return [row[::-1] for row in board]

# 滑动棋盘上的数字

def slide(board):

for i in range(4):

row = board[i]

row = [cell for cell in row if cell != 0]

row += [0] * (4 - len(row))

board[i] = row

return board

# 合并棋盘上相邻的相同数字

def merge(board):

for i in range(4):

row = board[i]

for j in range(3):

if row[j] == row[j + 1] and row[j] != 0:

row[j] *= 2

row[j + 1] = 0

return board

# 判断游戏是否结束

def is_game_over(board):

for row in board:

if 2048 in row:

return True

for i in range(4):

for j in range(4):

if board[i][j] == 0:

return False

if i < 3 and board[i][j] == board[i + 1][j]:

return False

if j < 3 and board[i][j] == board[i][j + 1]:

return False

return True

# 游戏主循环

def main():

board = create_board()

generate_number(board)

generate_number(board)

display_board(board)

while not is_game_over(board):

direction = input("请输入移动方向(上/下/左/右): if direction in ["上", "下", "左", "右"]:

board = move(board, direction_map[direction])

generate_number(board)

")

display_board(board)

else:

print("无效的移动方向!")

print("游戏结束!")

direction_map = {

"上": "up",

"下": "down",

"左": "left",

"右": "right"

}

if __name__ == "__main__":

main()

```

请注意,此代码仅实现了基本的2048游戏逻辑,可能并不完整或优化。您可以根据个人需求进行修改和扩展。


发布者:admin,转转请注明出处:http://www.yc00.com/news/1705561926a1412707.html

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